ruby-on-rails - Ruby - 如何根据以下模式摆脱字符串中的最后一个元素？

Question

我有这些字符串：

A regular sentence.
A regular sentence (United Kingdom).
A regular sentence (UK).

目标是删除括号中的术语，因此所需的输出将是：

A regular sentence.
A regular sentence.
A regular sentence.

如何在 Ruby 中实现这一点（可能使用正则表达式？）？

谢谢

score 3 · Accepted Answer

3

这应该有效：

string.gsub(/\s*\(.*\)/, '')

于 2013-10-23T10:28:34.350 回答

score 0 · Accepted Answer

0

"A regular sentence (UK).".gsub(/\(.*\)/,"").strip #=> "A regular sentence ."

于 2013-10-23T11:18:54.400 回答

score 0 · Accepted Answer

如果句子本身可以包含括号：

a = "A (very) regular sentence (UK)."
p a.gsub(/\s\([^()]*\)(?=\.\Z)/, '') #=> "A (very) regular sentence."

3 回答 3