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我正在尝试将表连接到其自身的子集，但遇到了麻烦。我的输入包含一个 ID 和一个日期，如下所示：

 2013-10-14 eca02319d91421445f82d570960c5d0c

 2013-10-15 eca02319d91421445f82d570960c5d0c

 2013-10-16 eca02319d91421445f82d570960c5d0c

 2013-10-17 eca02319d91421445f82d570960c5d0c

 2013-10-19 eca02319d91421445f82d570960c5d0c

 2013-10-21 eca02319d91421445f82d570960c5d0c

我的目标是确定每个日期的相同 id 的最后一个先前日期，例如：

     Date          ID                                 Last Date
  2013-10-21    eca02319d91421445f82d570960c5d0c     2013-10-19

  2013-10-19    eca02319d91421445f82d570960c5d0c     2013-10-17
  etc.

使用以下 SQL，我得到以下输出：

select a.Day,a.entity, b.Day from Visitor a
    LEFT OUTER JOIN Visitor b 
on a.entity = b.entity
       and b.day < a.day
where b.day is not null

 output

 2013-10-21 eca02319d91421445f82d570960c5d0c    2013-10-14

 2013-10-21 eca02319d91421445f82d570960c5d0c    2013-10-15

 2013-10-21 eca02319d91421445f82d570960c5d0c    2013-10-17

 2013-10-21 eca02319d91421445f82d570960c5d0c    2013-10-19

 2013-10-19 eca02319d91421445f82d570960c5d0c    2013-10-14

 2013-10-19 eca02319d91421445f82d570960c5d0c    2013-10-15

为 a.day 的每个实例以及按降序处理 b.day 的每个实例只获取一条记录需要什么？

先感谢您！

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1 回答 1

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尝试这样的事情：

SELECT distinct a.date, a.id, (select d.date from data d
        where a.date > d.date AND a.id = d.id
        order by d.date desc limit 1) as last_date 
FROM data a where (select d.date from data d
        where a.date > d.date AND a.id = d.id
        order by d.date desc limit 1) is not null
ORDER by a.date desc;

SQL小提琴

于 2013-10-23T06:49:41.740 回答