spring - 拦截器上的 Spring-ws 错误

Question

我的 spring-ws-servlet.xml 上有一个发布

当我启动 ws 我收到此错误：

cvc-complex-type.2.4.c: The matching wildcard is strict, but no declaration can be found for element 'ws:interceptors'.

这是有错误的行（spring-ws-servlet.xml）：

<ws:interceptors><bean class="com.nin.fi.sw.schema.WSLoggingInterceptor"/></ws:interceptors>

这是这些文件的标题：

    <?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"  
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:ws="http://www.springframework.org/schema/web-services"
    xmlns:util="http://www.springframework.org/schema/util"

    xsi:schemaLocation="http://www.springframework.org/schema/beans 
                        http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
                        http://www.springframework.org/schema/context
                        http://www.springframework.org/schema/context/spring-context-2.5.xsd
                        http://www.springframework.org/schema/web-services
                        http://www.springframework.org/schema/web-services/web-services-1.5.xsd
                        http://www.springframework.org/schema/util
                        http://www.springframework.org/schema/util/spring-util-2.0.xsd
                        http://www.springframework.org/schema/tx
                        http://www.springframework.org/schema/tx/spring-tx-2.5.xsd">

库：

我试图附加不同的 .xsd 但没有任何成功。我不知道我做错了什么。

Answer 1

您尚未为web-services

http://www.springframework.org/schema/web-services
http://www.springframework.org/schema/web-services/web-services-2.0.xsd