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我有两张桌子，我们称它们timeclock为 和time_tracker。

两个表都有timestamps输入，时间戳输出。time_tracker 仅在工作人员实际上在特定应用程序中时创建一个“time_in”条目，然后在他们将其工作标记为完成时创建一个“time_out”条目。

在给定的一天中，time_tracker 中将有几个这样的条目，而时钟中只有一个输入和一个输出。

我试图确定工作时间与打卡时间的对比，并以百分比形式呈现。

到目前为止，我所做的工作一直有效，直到我加入时钟表。当我这样做时，似乎时间会以某种方式成倍增加，我无法确定故障在哪里。

下面查询：

SELECT it.user_id, SUM(TIMESTAMPDIFF(minute, it.time_in, it.time_out) / 60) as `Total Time Clocked In`,
SUM(TIMESTAMPDIFF(minute, isb.start_time, isb.end_time) / 60) as `Total Time in Work`
FROM time.time_track isb
INNER JOIN time.timeclock it ON isb.user_id = it.user_id
WHERE it.time_in >= '2013-10-01 00:00:00' AND it.time_out <= '2013-10-01 23:59:59'
AND isb.start_time >= '2013-10-01 00:00:00' AND isb.end_time <= '2013-10-01 23:59:59'
AND it.user_id = '12';
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1 回答 1

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如果问题是您的“总打卡时间”太高，这应该可以解决问题。SUM从该表达式中删除函数。

SELECT it.user_id, TIMESTAMPDIFF(minute, it.time_in, it.time_out) / 60 as `Total Time Clocked In`,
SUM(TIMESTAMPDIFF(minute, isb.start_time, isb.end_time) / 60) as `Total Time in Work`
FROM time.time_track isb
INNER JOIN time.timeclock it ON isb.user_id = it.user_id
WHERE it.time_in >= '2013-10-01 00:00:00' AND it.time_out <= '2013-10-01 23:59:59'
AND isb.start_time >= '2013-10-01 00:00:00' AND isb.end_time <= '2013-10-01 23:59:59'
AND it.user_id = '12';

编辑- 我没有意识到特定日期的时钟表中可能有多个记录。以下语句应该在这种情况下工作。

SELECT  a.user_id, a.`Total Time Clocked In`, b.`Total Time in Work`

FROM

(
    SELECT  it.user_id, SUM(TIMESTAMPDIFF(minute, it.time_in, it.time_out)) / 60 as `Total Time Clocked In`

    FROM    time.timeclock it

    WHERE   it.time_in >= '2013-10-01 00:00:00' AND it.time_out <= '2013-10-01 23:59:59'
            AND it.user_id = '12'
) AS a

JOIN 

(
    SELECT  isb.user_id, SUM(TIMESTAMPDIFF(minute, isb.start_time, isb.end_time) / 60) as `Total Time in Work`

    FROM    time.time_track isb

    WHERE   isb.start_time >= '2013-10-01 00:00:00' AND isb.end_time <= '2013-10-01 23:59:59'
            AND isb.user_id = '12'

) AS b ON a.user_id = b.user_id
于 2013-10-22T14:06:23.687 回答