groovy - Groovy - 如何简化嵌入式函数参数

Question

我在 jenkins 中运行 groovy，我想从功能中拆分数据。我试图用变量名和值创建一个映射，但它看起来像函数内部的函数搞砸了。我想在不复制代码的情况下提取 CurrentBuildNo、ProjectName、Results_Folder（它们对于每个并行运行都不同）。

autotests = parallel (
  { ignore(ABORTED) { 
     retry ( 2 ) {
       build("AutoTest", CurrentBuildNo: CurrentBuildNo, ProjectName: params["ProjectName"], Results_Folder: Results_Folder) 
   } } },
  { ignore(ABORTED) { 
     retry ( 2 ) {
       build("AutoTest", CurrentBuildNo: CurrentBuildNo, ProjectName: params["ProjectName"], Results_Folder: Results_Folder) 
   } } }
)

我想要的逻辑是这样的：

tests = {{CurrentBuildNo: CurrentBuildNo, ...},{CurrentBuildNo: CurrentBuildNo, ...}}
autotests = parallel (
  for (i in tests){
     ignore(ABORTED) { 
        retry ( 2 ) {
           build("AutoTest", test[i]['CurrentBuildNo'], test[i]['ProjectName']...) 
      } } }
  }
)

Answer 1

啊，我想你会想要这样的东西：

def tests = [ [ CurrentBuildNo: CurrentBuildNo, ... ],
              [ CurrentBuildNo: CurrentBuildNo, ... ] ]

parallel tests.collect { t ->
    {
        ignore( ABORTED ) {
            retry( 2 ) {
                build( 'AutoTest', t.CurrentBuildNo, ... )
            }
        }
    }
}