sqlite - SQLite 3 - 如何从下面的代码中选择 MIN() 中的下一个值，以及如何为所有下一个、下一个 ... 值自动化它

Question

               MIN( CASE
                    WHEN Type = 435 THEN TimeStamp 
               END ) AS InTime,                   
               MIN( CASE
                    WHEN Type = 324 THEN TimeStamp 
               END ) AS OutTime

上面的代码使用 min() 找到最小值，如何找到下一个最小值以及如何获取所有下一个......值......

Answer 1

SELECT TimeStamp AS InTime
FROM MyTable
WHERE Type = 435
ORDER BY Timestamp;

SELECT TimeStamp AS OutTime
FROM MyTable
WHERE Type = 324
ORDER BY Timestamp;