0

我正在尝试将 Google Graph 的输出保存为图像并不断收到以下错误：

未捕获的类型错误：无法读取 null 的属性“firstChild”

这是javascript：

// Load the Visualization API and the piechart package.
google.load('visualization', '1.0', {'packages':['corechart']});

// Set a callback to run when the Google Visualization API is loaded.
google.setOnLoadCallback(drawChart);

// Callback that creates and populates a data table,
// instantiates the pie chart, passes in the data and
// draws it.
function drawChart() {
var data = google.visualization.arrayToDataTable([
    ['Date', 'Impressions', 'Clicks']
    <?
                while ($arrDate = mysql_fetch_assoc($resStats)) {
                    $arrDates[] = $arrDate;
                    echo ",['".$arrDate["fdate"]."', ".($arrDate["imps"] ? $arrDate["imps"] : 0).", ".($arrDate["clicks"] ? $arrDate["clicks"] : 0)."]";
                }
    ?>
]);

var options = {
    series: {
        0: {targetAxisIndex: 0},
        1: {targetAxisIndex: 1}
    },
    vAxes:{
        0: {title: 'Impressions', minValue: 0},
        1: {title: 'Clicks', minValue: 0}
    }
};

var chart = new google.visualization.LineChart(document.getElementById('chartContainer'));
chart.draw(data, options);
}

function getImgData(chartContainer) {
var chartArea = chartContainer.getElementsByTagName('svg')[0].parentNode;
var svg = chartArea.innerHTML;
var doc = chartContainer.ownerDocument;
var canvas = doc.createElement('canvas');
canvas.setAttribute('width', chartArea.offsetWidth);
canvas.setAttribute('height', chartArea.offsetHeight);


canvas.setAttribute(
    'style',
    'position: absolute; ' +
        'top: ' + (-chartArea.offsetHeight * 2) + 'px;' +
        'left: ' + (-chartArea.offsetWidth * 2) + 'px;');
doc.body.appendChild(canvas);
canvg(canvas, svg);
var imgData = canvas.toDataURL("image/png");
canvas.parentNode.removeChild(canvas);
return imgData;
}

function saveAsImg(chartContainer) {
var imgData = getImgData(chartContainer);

// Replacing the mime-type will force the browser to trigger a download
// rather than displaying the image in the browser window.
    window.location = imgData.replace("image/png", "image/octet-stream");
}

function toImg(chartContainer, imgContainer) {
var doc = chartContainer.ownerDocument;
var img = doc.createElement('img');
img.src = getImgData(chartContainer);

while (imgContainer.firstChild) {
    imgContainer.removeChild(imgContainer.firstChild);
}
imgContainer.appendChild(img);
}

那里的 PHP 部分输出如下：

['Date', 'Impressions', 'Clicks'],
['Aug 24, 2012', 2, 0],['Aug 27, 2012', 3, 0],['Aug 28, 2012', 37, 0],['Aug 29, 2012', 17, 0]

这是所需的按钮和 div：

<button onclick="toImg(document.getElementById('chartContainer'), document.getElementById('img_div'));">Convert to image</button>
<div id="line_div"></div>

这： http: //jsfiddle.net/SCjm8/157/是一个我试图遵循但被卡住的教程。有人可以告诉我如何制作它，以便当我单击代码中的按钮时，它会生成图像并将其放置在 Div 中？

非常感谢

4

0 回答 0