php - 将值存储在变量中并使用 PHP 打印它们

Question

有可能做这样的事情吗？我是新手所以不知道！

//row 1 in mysql array
$var = "hello"; 
$id = 1; 

//row 2 in mysql array
$var = "bye";
$id = 2;

//Closing while loop

//Is the following possible?
echo $var1; //outputs "hello"
echo $var2; //outputs "bye"

Answer 1

不像您想要的那样，您可以使用数组：

$var[1] = "hello";
$var[2] = "bye";

echo $var[1];
echo $var[2];

Answer 2

我会这样做

$id = 1; 
$var[$id] = "hello";
$id = 2;
$var[$id] = "bye";
echo $var['1']; 
echo $var['2']; 
// or
echo $var[$id];

Answer 3

// Define them both as arrays
$var = array();
$id = array();

// In your loop
$var[] = "hello";
$id[] = 1;

// Next iteration
$var[] = "bye";
$id[] = 2;

// Printing them out
echo $var[0]; // prints out "hello"
echo $var[1]; // prints out "bye"

使用数组^^

或者：

$rows = array();

// In your loop
$rows[] = array("id" => 1, "var" => "hello");

// Next iteration
$rows[] = array("id" => 2, "var" => "bye");

// Print them out
echo $rows[0]["var"]; // Prints hello
echo $rows[1]["var"]; // Prints bye

Answer 4

你提到了 MySQL。因此，您想要实现的更完整示例是：

$var = array();
$id  = array();
while ($row = mysql_fetch_assoc($result)) {
    $var[] = $row['text']; // don't know how the column is named
    $id[]  = $row['id'];
}

echo $row[0]; // hello
echo $row[1]; // bye

使用循环变量i：

$var = array();
$i = 1;
while ($row = mysql_fetch_assoc($result)) {
    $var[$i] = $row['text']; // don't know how the column is named
    $i++;
}

echo $row[1]; // hello
echo $row[2]; // bye