-1

我完全不熟悉从文件中读取数据，特别是 xml 文件。我的文件bin\debug夹中有一个 xml 文件，该 xml 文件如下所示：

<Companies>
    <Company>
        <Name>Name1</Name><Code>11014</Code>    
        <MaintenancePercentage>15.9</MaintenancePercentage>
        <Sales>
            <Sale>
                <Code>19538</Code>
                <Title>ABC</Title>
                <Date>2009-04-29T00:00:00</Date>
                <Category>Category1</Category>
                <Amount>6543.39</Amount>
            </Sale>
            <Sale>
                <Code>19539</Code>
                <Title>xyz</Title>
                <Date>2009-04-30T00:00:00</Date>
                <Category>Category2</Category>
                <Amount>654.39</Amount>
            </Sale>
        </Sales>
    </Company>

    <Company>
        <Name>Name1</Name><Code>11014</Code>     
        <MaintenancePercentage>15.9</MaintenancePercentage>
        <Sales>
            <Sale>
                <Code>19538</Code>
                <Title>ABC</Title>
                <Date>2009-04-29T00:00:00</Date>
                <Category>Category1</Category>
                <Amount>6543.39</Amount>
            </Sale>
            <Sale>
                <Code>19539</Code>
                <Title>xyz</Title>
                <Date>2009-04-30T00:00:00</Date>
                <Category>Category2</Category>
                <Amount>654.39</Amount>
            </Sale>
        </Sales>
    </Company>
</Companies>

这是我的课：

public class Company
{
    public string Name;
    public string Code;
    public double MaintenancePercentage;
    public double AverageSales;
    public double TotalSales;
    public double TotalMaintenanceFee;
    public List<Sales> Saleses;

}
public class Sales
{
    public string Code;
    public string Title;
    public DateTime DateTime;
    public string Category;
    public double Amount;
}

现在我想从 xml 文件中读取数据并存储它们。

如何从 xml 文件中读取值？

例如

var company = new Company();
company.Name = //name from xml file
//and so on
foreach(sales in company)
{
   sales.code = //code from xml file
   sales.title = //title from xml file
   //and so on
}

这是我到目前为止使用谷歌的搜索结果所做的，但我不知道现在该做什么

var doc = new XmlDocument();
doc.Load(@"export.xml");
var root = doc.DocumentElement;
if (root == null)
{
    return;
}
var company = root.SelectNodes("Company");
if (company == null)
{
    return;
}
else
{
    foreach (var companyData in company)
    {
        var title = 
    }
}

最后一段代码至少有意义吗？

4

2 回答 2

1

定义一个Companies类，它只包含一个列表Company，然后您可以使用以下代码行将整个批次反序列化为您的对象集：

var serializer = new XmlSerializer(typeof(Companies));
var reader = new StreamReader(pathToXmlFile);
var companies = (Companies)serializer.Deserialize(reader);
reader.Close();
于 2013-10-22T08:24:24.160 回答
0

假设您的 Test.XML 文件位于调试文件夹中

        var doc = (from e in XDocument.Load("Test.xml").Root.Elements("Company")
                           select new Company
                              {    
                                 name=(string)e.Element("name"),
                                 MaintenancePercentage=(double)e.Element("MaintenancePercentage"),
                                 Sales=(from sl in e.Elements("Sales").Elements("Sale")
                                     select new Sals
                                       {
                                          Code=(string)sl.Element("Code"),
                                          Title=(string)sl.Element("Title"),
                                          Datetime=(DateTime)sl.Elemnt("Date"),
                                          Category==(string)sl.Element("Category"),
                                          Amount=(double)sl.Element("Amount")

                                       }).ToArray()
                              }).ToList();
var company = new Company();
foreach(var Comp in doc)
{
    company.name=Comp.name;
    company.MaintenancePercentage=Comp.MaintenancePercentage;

}
var cSales=new Sales();
foreach(var salas in doc.Sales)
{

        cSales.Code=salas.Code;
        cSales.Title=salas.Title;
        pcSales.DateTime=salas.Datetime;
        cSales.Category=salas.Category;
       cSales.Amount=salas.Amount;
}

我希望你得到你的解决方案......

于 2015-07-17T10:53:24.353 回答