0

我在 armhf ubuntu 目标(arm9,omap4)上遇到了以下问题。我正在尝试使用 Ubuntu 12.04 arm-linux-gnueabihf 工具链执行 maliit 键盘。我成功交叉编译了 Qt5 和 maliit-framework 使用的不同库,但是在执行 maliit-server 或 maliit-exampleapp-plainqt 时,它会在打开动态库后立即退出。这是 strace 输出的结尾:

open("/mnt/internal/library/icu_4.8.1.1/lib/libicudata.so.48", O_RDONLY|O_CLOEXEC) = 3
read(3, "\177ELF\1\1\1\0\0\0\0\0\0\0\0\0\3\0(\0\1\0\0\0T\2\0\0004\0\0\0"..., 512) = 512
lseek(3, 18280604, SEEK_SET)            = 18280604
read(3, "\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0"..., 480) = 480
lseek(3, 18280460, SEEK_SET)            = 18280460
read(3, "A \0\0\0aeabi\0\1\26\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4,"..., 33) = 33
exit_group(1)                           = ?
+++ exited with 1 +++

我首先认为这与不同库之间的 arm 浮点不兼容有关,但是库上的 readelf -h 给了我这个(除了其中一些具有 Tag_ABI_optimization_goals: Aggressive Speed):

Attribute Section: aeabi
File Attributes
  Tag_CPU_name: "7-A"
  Tag_CPU_arch: v7
  Tag_CPU_arch_profile: Application
  Tag_ARM_ISA_use: Yes
  Tag_THUMB_ISA_use: Thumb-2
  Tag_FP_arch: VFPv3-D16
  Tag_ABI_PCS_wchar_t: 4
  Tag_ABI_FP_denormal: Needed
  Tag_ABI_FP_exceptions: Needed
  Tag_ABI_FP_number_model: IEEE 754
  Tag_ABI_align_needed: 8-byte
  Tag_ABI_align_preserved: 8-byte, except leaf SP
  Tag_ABI_enum_size: int
  Tag_ABI_HardFP_use: SP and DP
  Tag_ABI_VFP_args: VFP registers
  Tag_CPU_unaligned_access: v6
  Tag_DIV_use: Not allowed

我可以通过 strace 看到所有的库都已经找到了。在 strace 上搜索“aeabi”会给我以下输出:

read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\3\f"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A4\0\0\0aeabi\0\1*\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 53) = 53
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A6\0\0\0aeabi\0\1,\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4\22"..., 55) = 55
read(3, "A \0\0\0aeabi\0\1\26\0\0\0\0057-A\0\6\n\7A\10\1\t\2\n\4,"..., 33) = 33

ldd 也退出而不显示所需的所有不同库并返回 1。

有谁知道这里发生了什么?

4

0 回答 0