0 
def convertSeq(s, index):
    result = [i+1 for i,ch in enumerate(s) if ch=='1']
    result = ' '.join([str(index)+':'+str(i) for i in result])
    result = str(index)+' '+result
    return result
seq1 = "00001000000000000000000010000000000000000000100000000000000000001000000000000000"

a = convertSeq(seq1, 1)
print a

给定的functoin已被创建来转换

"00001000000000000000000010000000000000000000100000000000000000001000000000000000"

如果我使用特定位置的代码，它的工作正常

seq1 = "00001000000000000000000010000000000000000000100000000000000000001000000000000000"

作为我得到的代码的输入，

 1 1:5 1:25 1:45 1:65

作为输出（如预期）。但是当我使用包含内容的输入文件时：

00001000000000000000000010000000000000000000100000000000000000001000000000000000 
10000000000000000000001000000000000000000010000000000000000000100000000000000000 
00100000000000000000001000000000000000000010000000000000000000100000000000000000

输出很奇怪。

在我看来，当我使用

seq1="00001000000000000000000010000000000000000000100000000000000000001000000000000000"

它被认为是一个字符串，因为" "当我使用输入文件时，它会将其视为0单个1字符。

我应该使用什么方法，以便它可以从包含行中二进制代码的文件中获取二进制代码输入，并为每一行生成输出。

样本输入：

00001000000000000000000010000000000000000000100000000000000000001000000000000000
10000000000000000000001000000000000000000010000000000000000000100000000000000000
00100000000000000000001000000000000000000010000000000000000000100000000000000000
00001000000000000000000010000000000000000000100000000000000000001000000000000000
10000000000000000000001000000000000000000010000000000000000000100000000000000000
00100000000000000000001000000000000000000010000000000000000000100000000000000000

样本输出：

1 1:5 1:25 1:45 1:65
2 2:1 2:21 2:44 2:64
and so on...........

由于我是编程新手，我花了 5-6 个小时在上面，但没有成功。请帮忙

4

3 回答 3

2

如果convertSeq可行，那么应该这样做：

line_num = 1
for line in open(filename):
    print convertSeq(line, line_num)
    line_num += 1
于 2013-10-21T09:06:25.517 回答
1

您可以这样做，将整个文件作为字符串读取并传递给您的函数

def convertSeq(s, index):
    result = [i+1 for i,ch in enumerate(s) if ch=='1']
    result = ' '.join([str(index)+':'+str(i) for i in result])
    result = str(index)+' '+result
    return result

# read the sequence from file
with open ("file.txt",'r') as f:
   f_seq=f.readlines()

for line, seq in enumerate(f_seq, start=1):
    a = convertSeq(seq, line)
    print a

根据您提供的内容，它提供以下输出

1 1:5 1:25 1:45 1:65
2 2:1 2:23 2:43 2:63
3 3:3 3:23 3:43 3:63
4 4:5 4:25 4:45 4:65
5 5:1 5:23 5:43 5:63
6 6:3 6:23 6:43 6:63

您还可以将文件名作为 arg 读取到程序中，因此您不必对文件名进行硬编码

import sys
def convertSeq(s, index):
    result = [i+1 for i,ch in enumerate(s) if ch=='1']
    result = ' '.join([str(index)+':'+str(i) for i in result])
    result = str(index)+' '+result
    return result

#take the file name as arg
seqFile = sys.argv[1]

with open (seqFile,'r') as f:
   f_seq=f.readlines()

for line, seq in enumerate(f_seq, start=1):
    a = convertSeq(seq, line)
    print a
于 2013-10-21T09:08:10.070 回答
1

使用来遍历文件enumerate()以计算行数：

with open(filename) as f:
    for line_no, seq in enumerate(f, start=1):
        print convertSeq(seq, line_no)
于 2013-10-21T09:17:01.983 回答