我有四张桌子:
PAINTING GALLERY ARTIST PAINTED
- PAINTING_TITLE - GALLERY_ID - ARTIST_ID - PAINTED_CODE
- PAINTING_ID - GALLERY_NAME - ARTIST_LAST - ARTIST_ID
- ARTIST_FIRST - PAINTING_ID
PAINTED 表记录了每位艺术家绘制的画作。有些画是由不止一位艺术家绘制的。我想返回两位艺术家绘制的画作列表。
SELECT PAINTING.PAINTING_TITLE AS TITLE,
GALLERY.GALLERY_NAME AS GALLERY,
ARTIST.ARTIST_FIRST AS ARTISTFIRST,
ARTIST.ARTIST_LAST AS ARTISTLAST
FROM PAINTING, GALLERY, PAINTED, ARTIST
WHERE PAINTING.GALLERY_ID = GALLERY.GALLERY_ID
AND PAINTING.PAINTING_ID = PAINTED.PAINTING_ID
AND ARTIST.ARTIST_ID = PAINTED.ARTIST_ID
AND (SELECT COUNT(*) FROM PAINTED, PAINTING, ARTIST
WHERE PAINTING.GALLERY_ID = GALLERY.GALLERY_ID
AND PAINTING.PAINTING_ID = PAINTED.PAINTING_ID
AND ARTIST.ARTIST_ID = PAINTED.ARTIST_ID) = 2;
这不会返回我需要的结果。你对如何只选择有两位艺术家的画作有什么想法吗?
我正在使用 Access SQL,任何帮助将不胜感激。