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嘿，stackoverflow 社区！

我目前正在开发一个游戏间+服务器间项目，但我卡在了我的身份验证系统上。当我使用一些正确的详细信息登录时，我得到了错误

 Notice: Undefined index: myusername in C:\wamp\www\new\panel.php on line 8
 Notice: Undefined index: mypassword in C:\wamp\www\new\panel.php on line 9

 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in C:\wamp\www\new\panel.php on line 13

我不知道如何解决这个问题，所以我要问的是如何解决这个问题？

这是我用来检查登录详细信息的代码：

<?php

ob_start();
$host="localhost"; // Host name
$username="mindfulbank"; // Mysql username
$password=""; // Mysql password
$db_name="mindful_bank"; // Database name
$tbl_name="members"; // Table name

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("Database cannot connect securely, please check back later!");
mysql_select_db("$db_name")or die("Database Cannot Be Selected");

// Define $myusername and $mypassword
$myusername=$_POST['myusername'];
$password=$_POST['mypassword'];
$sha1password=sha1($password);
$mypassword=md5($sha1password);

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);

// If result matched $myusername and $mypassword, table row must be 1 row

if($count==1){

// Register $myusername, $mypassword and redirect to file "login_success.php"
$_SESSION['myusername']=$myusername;
$_SESSION['mypassword']=$mypassword;
session_start();
header("location:panel.php");
}
else {
echo "Wrong Username or Password";
}

ob_end_flush();
?>

以及这些错误实际导致错误的页面：

<?php
session_start();

if(isset($_SESSION['myusername'])){
header("location:logout.php");
}

$myusername=$_SESSION['myusername'];
$mypassword=$_SESSION['mypassword'];
$con=mysqli_connect("localhost","mindfulbank","","mindful_bank");
$result = mysqli_query($con,"SELECT level FROM members WHERE password = '$mypassword' and username = '$myusername'");
$fname = mysqli_query($con,"SELECT name FROM members WHERE password = '$mypassword' and username = '$myusername'");
while($row = mysqli_fetch_array($result))
{  
  if($row['admin'] == 1){
   require 'panel/admindash.php';
 }
 else
 {
   require 'panel/userdash.php';
}
}
?>
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3 回答 3

1

将用于检查登录详细信息的脚本上的连接更新mysqli为mysql已折旧。

完成后将mysql_real_escape_string($myusername);功能更改为mysqli_real_escape_string($your_connection, $myusername);.

mysqli_real_escape_string期望 db 连接作为必需参数。

http://php.net/manual/en/mysqli.real-escape-string.php

然后添加session_start();到用于检查登录详细信息的脚本的顶部！

http://php.net/manual/en/function.session-start.php

希望这可以帮助

于 2013-10-20T16:33:38.587 回答
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您还需要第一个文件中的 session_start() 。

于 2013-10-20T16:28:39.347 回答
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session_start()发生前两个错误是因为您之前没有$_SESSION在第一个脚本中编写。始终将其写在脚本的顶部。最后一个错误是因为运行该查询没有得到任何结果。$result->num_rows > 0在进一步操作之前始终检查。

于 2013-10-20T16:39:08.977 回答