4

Python 3.3.2 导入 json & urllib.request

json

[{"link":"www.google.com","orderid":"100000222"},
{"link":"www.google.com","orderid":"100000222"},
{"link":"www.google.com","orderid":"100000222"}]

打印(响应信息())

Date: Sun, 20 Oct 2013 07:06:51 GMT
Server: Apache
X-Powered-By: PHP/5.4.12
Content-Length: 145
Connection: close
Content-Type: application/json

代码

url = "http://www.Link.com"
    request = urllib.request.Request(url)
    request.add_header('User-Agent','Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)')
    request.add_header('Content-Type','application/json')
    response = urllib.request.urlopen(request)

    decodedRes = response.read().decode('utf-8')
    json_object = json.load(decodedRes)

以下是我的代码错误

Traceback (most recent call last):
  File "C:\Users\Jonathan\Desktop\python.py", line 57, in <module>
    checkLink()
  File "C:\Users\Jonathan\Desktop\python.py", line 50, in checkLink
    json_object = json.load(decodedRes)
  File "C:\Python33\lib\json\__init__.py", line 271, in load
    return loads(fp.read(),
AttributeError: 'str' object has no attribute 'read'
>>> .

知道如何解决这个问题吗?

4

4 回答 4

19

使用json.loads而不是json.load.

json.loads(decodedRes)

>>> import json
>>> json.load('{"a": 1}')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "C:\Python27\lib\json\__init__.py", line 286, in load
    return loads(fp.read(),
AttributeError: 'str' object has no attribute 'read'
>>> json.loads('{"a": 1}')
{u'a': 1}

或者,您可以将响应对象传递给json.load

## decodedRes = response.read().decode('utf-8')
json_object = json.load(response)
于 2013-10-20T07:10:36.020 回答
4

尝试将 替换json.load()json.loads()。前者需要一个文件流,这就是您遇到属性错误的原因。

于 2013-10-20T07:21:12.720 回答
4

以下代码将 json 文件加载到文档中。文档将具有 dict 类型的值。

file_name = "my_file.json"
with open(file_name, 'r') as f:
    document =  json.loads(f.read())
于 2020-05-21T13:37:31.463 回答
0

很简单,你只需要用另一种方式导入漂亮的汤。现在您正在导入为

from beautifulSoup import BeautifulSoup

将其更改为

from bs4 import BeautifulSoup
于 2016-09-17T14:39:59.873 回答