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我已加入两个表值并将这些值插入另一个表中，但插入不起作用。我正在使用 Access 数据库，并且正在使用以下代码：

 string query = "select t2.date,t1.FlightNo,t1.Dept_Time,t1.Arr_Time,t1.Route,t1.[Destination 1],t1.[Destination 2],t1.[Destination 3],t1.[Destination 4] From [FlightNumber]as t1 inner join [schedule]as t2 on t1.FlightNo=t2.FlightNo";

 OleDbCommand cmd = new OleDbCommand(query, con);

 OleDbDataAdapter adp = new OleDbDataAdapter(cmd);
 dt1 = new DataTable();
 adp.Fill(dt1);
 con.Open();
 string query2 = "Insert into Monday (date,[Flight_no],[Dept_time],[Arr_time],Route,[dest_1],dest2,dest3,dest4)values(@date,@flight,@dept,@arr,@route,@dest1,@dest2,@dest3,@dest4)";
 for (int i = 0; i < dt1.Rows.Count; i++)
 {
     OleDbCommand cmd1 = new OleDbCommand(query2, con);

     cmd.Parameters.AddWithValue("@date", SqlDbType.NVarChar).Value = dt1.Rows[i]["date"].ToString();
     cmd.Parameters.AddWithValue("@flight", dt1.Rows[i]["FlightNo"]);
     cmd.Parameters.AddWithValue("@dept", dt1.Rows[i]["Dept_Time"]);
     cmd.Parameters.AddWithValue("@arr", dt1.Rows[i]["Arr_Time"]);
     cmd.Parameters.AddWithValue("@route", dt1.Rows[i]["Route"]);
     cmd.Parameters.AddWithValue("@dest1", dt1.Rows[i]["Destination 1"]);
     cmd.Parameters.AddWithValue("@dest2", dt1.Rows[i]["Destination 2"]);
     cmd.Parameters.AddWithValue("@dest3", dt1.Rows[i]["Destination 3"]);
     cmd.Parameters.AddWithValue("@dest4", dt1.Rows[i]["Destination 4"]);

     cmd1.ExecuteNonQuery();
     con.Close();
     MessageBox.Show("successfully inserted");            
 }
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2 回答 2

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DATE是 Access SQL 中的保留字，因此您需要在 INSERT 命令中将该列名包含在方括号中（就像您对 [Flight_no]、[Dept_time] 等所做的那样）。

string query2 = "Insert into Monday ([date], ...
于 2013-10-19T19:15:24.333 回答
0

除了 Gord 提到的保留字 Date 之外，如果您不继续重建命令和参数，您的性能可能会更好，尤其是当您尝试插入大量记录时。相反，做类似...

string query2 = "Insert into Monday (date,[Flight_no],[Dept_time],[Arr_time],Route,[dest_1],dest2,dest3,dest4)values(@date,@flight,@dept,@arr,@route,@dest1,@dest2,@dest3,@dest4)";

// 预构建命令和参数 ONCE
OleDbCommand cmd1 = new OleDbCommand(query2, con);

cmd.Parameters.AddWithValue("@date", dt1.Rows[i]["date"].ToString() ); cmd.Parameters.AddWithValue("@flight", dt1.Rows[i]["FlightNo"]); cmd.Parameters.AddWithValue("@dept", dt1.Rows[i]["Dept_Time"]); cmd.Parameters.AddWithValue("@arr", dt1.Rows[i]["Arr_Time"]); cmd.Parameters.AddWithValue("@route", dt1.Rows[i]["Route"]); cmd.Parameters.AddWithValue("@dest1", dt1.Rows[i]["Destination 1"]); cmd.Parameters.AddWithValue("@dest2", dt1.Rows[i]["Destination 2"]); cmd.Parameters.AddWithValue("@dest3", dt1.Rows[i]["Destination 3"]); cmd.Parameters.AddWithValue("@dest4", dt1.Rows[i]["Destination 4"]);

 for (int i = 0; i < dt1.Rows.Count; i++)
 {
     cmd.Parameters[0].Value = dt1.Rows[i]["date"].ToString();
     cmd.Parameters[1].Value = dt1.Rows[i]["FlightNo"]);
     cmd.Parameters[2].Value = dt1.Rows[i]["Dept_Time"]);
     cmd.Parameters[3].Value = dt1.Rows[i]["Arr_Time"]);
     cmd.Parameters[4].Value = dt1.Rows[i]["Route"]);
     cmd.Parameters[5].Value = dt1.Rows[i]["Destination 1"]);
     cmd.Parameters[6].Value = dt1.Rows[i]["Destination 2"]);
     cmd.Parameters[7].Value = dt1.Rows[i]["Destination 3"]);
     cmd.Parameters[8].Value = dt1.Rows[i]["Destination 4"]);

     cmd1.ExecuteNonQuery();
 }

 con.Close();
 MessageBox.Show("successfully inserted");
于 2013-10-21T12:13:03.253 回答