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public void readSMS() {
        System.out.println("Inside of SMS Reading.......");
        Uri SMSURI = Uri.parse("content://sms/inbox");
        String[] projection = new String[] { "_id", "address", "body", "date" };
        Cursor cursor = null;

        try {
            System.out.println("Inside of SMS Reading Try.......");
            cursor = getContentResolver().query(SMSURI, projection, null // selection
                    , null // selectionArgs
                    , null); // sortOrder

            if (cursor != null && cursor.moveToFirst()) {
                do {
                    // System.out.println("Inside of SMS Reading DO.......");
                    int id = cursor.getInt(cursor.getColumnIndex("_id"));
                    String address = cursor.getString(cursor
                            .getColumnIndex("address"));
                    String body = cursor.getString(cursor
                            .getColumnIndex("body"));
                    String date = cursor.getString(cursor
                            .getColumnIndex("date"));

                    SMSNo.add(address);
                    SMSText.add(body);
                    SMSType.add("Incoming");
                    SMSTime.add(getSMSTime(Long.parseLong(date)));

                } while (cursor.moveToNext());

                // readOutgoingSMS();
            }

        } catch (Exception e) {
            System.out.println("Error = " + e.toString());

        } finally {
            if (cursor != null) {
                cursor.close();
            }
        }
    }

我正在开发一个应用程序，用户可以在其中将他们的消息上传到服务器，并可以随时下载它们。但是我收到了一个非常奇怪的错误。每当我在默认消息中收到一条消息时，它都会向我显示 2 条消息，其中一条是加密的。它还向我展示了我的应用程序已停止工作的祝酒词。谁能告诉我为什么会这样？

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0 回答 0