我正在尝试遍历来自 SOAP 请求的一些数据,并将记录插入到我的 Drupal 安装中的自定义表中。
起初,我创建了一个自定义模块并使用标准mysqli_connect()
语法连接到数据库并遍历记录并插入它们。这工作得很好,并且在大约 2 秒内顺利地获取并插入了我的远程数据。
然后我记得 Drupal 有一个数据库 API(我对 Drupal 还很陌生),所以我决定做正确的事并改用 API。我将我的代码转换为我认为我应该按照 API 文档执行的方式,但现在该过程需要 5 或 6 秒,有时甚至随机挂起并且根本没有完成,并且我得到了奇怪的会话错误。记录最终插入得很好,但它只需要永远。
我想知道我是否做错了。我还想将插入包装到事务中,因为我将首先删除目标表中的所有记录,然后插入新数据,因为我首先删除,所以我希望能够回滚,如果插入因任何原因而失败。
我没有将事务代码添加到我原来的纯 PHP 代码中,但确实尝试使用 Drupal API 尝试它,尽管完全删除事务/尝试/捕获代码似乎根本不会影响速度或问题。
无论如何,这是我的原始代码:
$data = simplexml_load_string($jobsXml);
$connection = mysqli_connect("localhost","user","pass","database");
if (mysqli_connect_errno($connection))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
exit();
}
// delete * current jobs
mysqli_query($connection,'TRUNCATE TABLE jobs;');
$recordsInserted = 0;
foreach ($data->NewDataSet->Table as $item) {
//escape and cleanup some fields
$image = str_replace('http://www.example.com/public/images/job_headers/', '', $item->job_image_file);
$specialty_description = mysqli_real_escape_string($connection, $item->specialty_description);
$job_board_title = mysqli_real_escape_string($connection, $item->job_board_title);
$job_board_subtitle = mysqli_real_escape_string($connection, $item->job_board_subtitle);
$job_state_code = ($item->job_country_code == 'NZ') ? 'NZ' : $item->job_state_code;
$sql = "
INSERT INTO jobs (
job_number,
specialty,
specialty_description,
division_code,
job_type,
job_type_description,
job_state_code,
job_country_code,
job_location_display,
job_board_type,
job_image_file,
job_board_title,
job_board_subtitle
) VALUES (
$item->job_number,
'$item->specialty',
'$specialty_description',
'$item->division_code',
'$item->job_type',
'$item->job_type_description',
'$job_state_code',
'$item->job_country_code',
'$item->job_location_display',
'$item->job_board_type',
'$image',
'$job_board_title',
'$job_board_subtitle'
)
";
if (!mysqli_query($connection,$sql))
{
die('Error: ' . mysqli_error($connection) . $sql);
}
$recordsInserted++;
}
mysqli_close($connection);
echo $recordsInserted . ' records inserted';
这是我的 Drupal 代码。谁能告诉我我做错了还是不是最有效的方法?
$data = simplexml_load_string($jobsXml);
// The transaction opens here.
$txn = db_transaction();
// delete all current jobs
$records_deleted = db_delete('jobs')
->execute();
$records_inserted = 0;
try {
$records = array();
foreach ($data->NewDataSet->Table as $item) {
$records[] = array(
'job_number' => $item->job_number,
'specialty' => $item->specialty,
'specialty_description' => $item->specialty_description,
'division_code' => $item->division_code,
'job_type' => $item->job_type,
'job_type_description' => $item->job_type_description,
'job_state_code' => ($item->job_country_code == 'NZ') ? 'NZ' : $item->job_state_code,
'job_country_code' => $item->job_country_code,
'job_location_display' => $item->job_location_display,
'job_board_type' => $item->job_board_type,
'job_image_file' => str_replace('http://www.example.com/public/images/job_headers/', '', $item->job_image_file),
'job_board_title' => $item->$job_board_title,
'job_board_subtitle' => $item->job_board_subtitle,
);
$records_inserted++;
}
$fields = array(
'job_number',
'specialty',
'specialty_description',
'division_code',
'job_type',
'job_type_description',
'job_state_code',
'job_country_code',
'job_location_display',
'job_board_type',
'job_image_file',
'job_board_title',
'job_board_subtitle'
);
$query = db_insert('jobs')
->fields($fields);
foreach ($records as $record) {
$query->values($record);
}
$query->execute();
} catch (Exception $e) {
// Something went wrong somewhere, so roll back now.
$txn->rollback();
// Log the exception to watchdog.
watchdog_exception('Job Import', $e);
echo $e;
}
echo $records_deleted . ' records deleted<br>';
echo $records_inserted . ' records inserted';