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我在 Matlab 中制作了一个图表，如果该点在指定的框内，则生成点并绘制一个红色十字，如果它在外面，则绘制一个蓝色圆圈。绘图工作正常，但我发现传说的产生很难正确。仅在绘图末尾添加图例仅显示与绘制的最后一个点相对应的条目。

我最终使用下面的代码让它工作，通过为创建的第一个点创建一个图例，然后在绘制另一种类型的点时，获取当前图例并将新点信息附加到其中。

这看起来真的很啰嗦，有没有更好的方法来为这种绘制点的方式生成图例？

figure;
title('A Graph') ;
hold on;
redhandle = 0
bluehandle = 0
redlegendmade = 0;
bluelegendmade = 0;
for count1 = 1:100
  % Get a random point in a circle with radius 5
  random_radius = sqrt(5)*rand(); 
  random_angle = 2*pi*rand; 

  % Set x and y coordinates. 
  x = random_radius*cos(random_angle); 
  y = random_radius*sin(random_angle); 

  % If point inside a box,centred on 0,0 with width = 4 and 
  % height = 2, draw a red cross, otherwise a blue circle.
  if (abs(x)< 2 && abs(y)<1) 
    % Get a handle to a plotted red point for legend
    redhandle = plot(x,y,'rx');

    % Actually plot the red point so its visible
    plot(x,y,'rx');

    % If we haven't already handled the red info for the legend, do so
    if (redlegendmade == 0)
      % Get current legend
      [LEGH,OBJH,OUTH,OUTM] = legend;

      % Update legend with red info
      legend([OUTH;redhandle],OUTM{:},'In')

      % Don't handle red info again
      redlegendmade = 1;
    end
    hold on;
  else
    % Get handle to plotted blue point for adding to legend
    bluehandle = plot(x,y,'bo');

    % Actually plot the blue point so it's visible
    plot(x,y,'bo');

    % If we havent already handled the blue info for legend, do so
    if (bluelegendmade == 0)
      % Get current legend
      [LEGH,OBJH,OUTH,OUTM] = legend;

      % Update legend with blue info
      legend([OUTH;bluehandle],OUTM{:},'Out')

      % Don't handle blue info again
      bluelegendmade = 1
    end
    hold on;
  end
end
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1 回答 1

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您可以为每个点设置一个图例句柄，然后只使用第一个和最后一个。

figure;
hold on;
for ii = 1:10
    if ii<5
        h(ii,1) = plot(rand,rand,'rx');
    else
        h(ii,1) = plot(rand,rand,'bo');
    end
end
legend([h(1) h(end)],{'red', 'blue'})

您可以根据绘制点的顺序更改1和索引。end

于 2013-10-18T18:11:01.333 回答