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我必须将数据从以前的应用程序版本迁移到新版本。这也会影响用户保存的一些谓词(NSPredicate实例),这意味着我必须以编程方式更改它们。

目前我尝试解析我得到的字符串[NSPredicate predicateFormat]并手动更改一些表达式。例如oldKeyPath == "something"newKeyPath == "something". 但这感觉就像一个黑客,我很好奇是否有更好的方法?

我阅读了 Apple 关于使用 NSPredicate 和 NSExpression 进行编程的文档。有很多方法可以NSPredicateNSExpressions. 我希望找到NSExpressionNSPredicate. 我错过了什么吗?

谢谢你的任何提示。

解决方案

感谢 Martin RI 能够创建一个类别NSPredicate,允许我对表达式进行修改。

@implementation NSPredicate (ExtractComparisions)

- (NSPredicate *)predicateByChangingComparisionsWithBlock:(NSPredicate *(^)(NSComparisonPredicate *))block {
  if ([self isKindOfClass: [NSCompoundPredicate class]]) {
    NSCompoundPredicate *compPred = (NSCompoundPredicate *)self;
    NSMutableArray *predicates = [NSMutableArray array];
    for (NSPredicate *predicate in [compPred subpredicates]) {
      NSPredicate *newPredicate = [predicate predicateByChangingComparisionsWithBlock: block];
      if (newPredicate != nil)
        [predicates addObject: newPredicate];
    }
    return [[[NSCompoundPredicate alloc] initWithType: compPred.compoundPredicateType
                                       subpredicates: predicates] autorelease];
  } if ([self isKindOfClass: [NSComparisonPredicate class]]) {
    return block((NSComparisonPredicate *)self);
  }
  return self;
}

@end

这是有关如何使用它的示例代码

- (void)applicationDidFinishLaunching:(NSNotification *)aNotification
{
  NSPredicate *predicate = [NSPredicate predicateWithFormat: @"key.path like %@ and count > 17", @"Hello"];
  NSPredicate *newPredicate = [predicate predicateByChangingComparisionsWithBlock:
                               ^NSPredicate *(NSComparisonPredicate *cp) {
    NSExpression *left = [cp leftExpression];
    NSExpression *right = [cp rightExpression];
    if ([[cp leftExpression] expressionType] == NSKeyPathExpressionType) {
      NSString *keyPath = [[cp leftExpression] keyPath];
      if ([keyPath isEqualToString: @"key.path"])
        left = [NSExpression expressionForKeyPath: @"key.new.path"];
      return [NSComparisonPredicate predicateWithLeftExpression: left
                                                rightExpression: right
                                                       modifier: cp.comparisonPredicateModifier
                                                           type: cp.predicateOperatorType
                                                        options:cp.options];
    }
    return cp;
  }];
  NSLog(@"Before: %@", predicate);
  NSLog(@"After: %@", newPredicate);
}
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1 回答 1

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(这只是一个想法。)每个谓词都是类似 NSCompoundPredicateor的子类的一个实例NSComparisonPredicate。因此,您可以检查谓词的实际类,将其强制转换为该类的对象,然后检查其属性。如有必要,使用子谓词或表达式重复该过程。

以下只是一个简单的复合谓词如何以这种方式“剖析”的示例。它不是检查所有情况的通用解决方案,但可能会为您指明正确的方向。

NSPredicate *p0 = [NSPredicate predicateWithFormat:@"foo = 'bar' AND count > 17"];

if ([p0 isKindOfClass:[NSCompoundPredicate class]]) {
    NSCompoundPredicate *p0a = (NSCompoundPredicate *)p0;
    NSCompoundPredicateType type0 = p0a.compoundPredicateType;  // NSAndPredicateType
    NSPredicate *p1 = p0a.subpredicates[0];                     // foo = 'bar'
    NSPredicate *p2 = p0a.subpredicates[1];                     // count > 17
    if ([p1 isKindOfClass:[NSComparisonPredicate class]]) {
        NSComparisonPredicate *p1a = (NSComparisonPredicate *)p1;
        NSPredicateOperatorType type1 = p1a.predicateOperatorType;  // NSEqualToPredicateOperatorType
        NSExpression *e3 = p1a.leftExpression;                  // foo, NSKeyPathExpression
        NSExpression *e4 = p1a.rightExpression;                 // "bar", NSConstantValueExpression
    }
    if ([p2 isKindOfClass:[NSComparisonPredicate class]]) {
        NSComparisonPredicate *p2a = (NSComparisonPredicate *)p2;
        NSPredicateOperatorType type2 = p2a.predicateOperatorType;  // NSGreaterThanPredicateOperatorType
        NSExpression *e5 = p2a.leftExpression;                  // count, NSKeyPathExpression
        NSExpression *e6 = p2a.rightExpression;                 // 17, NSConstantValueExpression
    }
}
于 2013-10-18T16:15:49.453 回答