1

我的 MySQL 表中有三个相同的表，即

first_term_result、second_term_result 和 third_term_result

这是其中的列

exam_type_id | student_id  | subject_id  | mark  |

或带有虚拟数据的示例

注意：每个科目有三种不同的考试类型（CA1、CA2、CA3 和考试），有三个像这样的表格，内容相同但数据不同，因为它保存第一学期的数据，第二学期的数据和第三学期的最后一个数据.

first_term_result:

exam_type_id | student_id  | subject_id  | mark  |
    1        |    6        |     7       | 12    |
    2        |    6        |     7       | 9     |
    3        |    6        |     7       | 13    |   
    4        |    6        |     7       | 45    |
    1        |    4        |     7       | 7     |
    2        |    4        |     7       | 5     |
    3        |    4        |     7       | 10    |   
    4        |    4        |     7       | 34    |

second_term_result:

exam_type_id | student_id  | subject_id  | mark  |
    1        |    6        |     7       | 15    |
    2        |    6        |     7       | 6     |
    3        |    6        |     7       | 10    |   
    4        |    6        |     7       | 50    |
    1        |    4        |     7       | 6     |
    2        |    4        |     7       | 3     |
    3        |    4        |     7       | 9     |   
    4        |    4        |     7       | 44    |


third_term_result:

exam_type_id | student_id  | subject_id  | mark  |
    1        |    6        |     7       | 17    |
    2        |    6        |     7       | 8     |
    3        |    6        |     7       | 15    |   
    4        |    6        |     7       | 67    |
    1        |    4        |     7       | 12    |
    2        |    4        |     7       | 8     |
    3        |    4        |     7       | 12    |   
    4        |    4        |     7       | 50    |

现在我想要实现的是按学生姓名获取每个SUM()学生的subject_id=7 组。first_term_result.mark second_term_result.markthird_term_result.markWHERE

另一个非常重要的问题是我将为每个学生计算 first_term+second_term+third_term 的总和，并且还希望能够为该学生和 DESC 中的科目订购总和，所以如果可以的话，我可以相应地定位它们在php上更容易请告诉我。

谢谢

这对我来说似乎很复杂，但我知道这里有大师可以做到这一点，我在某处读到即使使用汇总也可以订购。

下面是我的代码，它显然不起作用。

SELECT CONCAT(s.fname,' ',s.mname,' ',s.lname) AS sname, 
SUM(f.mark) AS first_total, 
SUM(se.mark) AS second_total, 
SUM(t.mark) AS third_total 
SUM(f.first_total,second.total,third_total) as GT // just to show my intention 
FROM students s, first_term_result f, second_term_result se, third_term_result t 
WHERE s.studentID=f.student_id AND
s.studentID=se.student_id AND
s.studentID=t.student_id AND
f.subject_id=7 AND
se.subject_id=7 AND
t.subject_id=7
GROUP BY sname ORDER BY GT DESC
4

1 回答 1

1 
SELECT CONCAT(MS.fname,' ',MS.mname,' ',MS.lname) AS sname, 
  M.FTotal, M.STotal, M.TTotal, 
  (M.FTotal + M.STotal + M.TTotal) AS GrandTotal
FROM (
  SELECT st.studentID, 
     (
       SELECT SUM(f.mark) 
       FROM first_term_result AS f 
       WHERE f.subject_id = 7 
       AND f.student_id = st.studentID
     ) AS FTotal, 
     (
       SELECT SUM(s.mark) 
       FROM second_term_result AS s 
       WHERE s.subject_id = 7 
       AND s.student_id = st.studentID
     ) AS STotal, 
     (
       SELECT SUM(t.mark) 
       FROM third_term_result AS t 
       WHERE t.subject_id = 7 
       AND t.student_id = st.studentID
     ) AS TTotal
  FROM students AS st
  WHERE st.studentID IN (
    SELECT studentID 
    FROM first_term_result AS fs 
    WHERE fs.subject_id = 7 
    AND fs.student_id = st.studentID)
  GROUP BY st.studentID
) AS M
JOIN students MS ON M.studentID = MS.studentID
ORDER BY (M.FTotal + M.STotal + M.TTotal) DESC
于 2013-10-18T13:44:10.523 回答