3

我正在开发循环赛,我有问题如何设计数据库。

首先我有季节。赛季包含锦标赛列表。锦标赛包含组列表。组包含列表参与者。然后我有球员名单。玩家和参与者的区别在于参与者是属于组的注册玩家。然后我有由 2 名参与者和他们的分数定义的实体游戏。所以参与者有游戏列表。

P = 参与者 G = 游戏

   P1 P2 P3
P1 X  G1 G2
P2 G3 X  G4
P3 G5 G6 X

这是我比赛的好模型吗?我不这么认为,因为我的数据库中有双重性。G1 与 G3 正好相反,但我不知道如何更好地实现这个模型

-- --------------------------------------------------------

--
-- Table structure for table `GAME`
--

CREATE TABLE IF NOT EXISTS `GAME` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `HOME_PARTICIPANT_ID` int(11) NOT NULL,
  `AWAY_PARTICIPANT_ID` int(11) NOT NULL,
  `HOME_SCORE` int(4) DEFAULT NULL,
  `AWAY_SCORE` int(4) DEFAULT NULL,
  PRIMARY KEY (`ID`),
  KEY `HOME_PARTICIPANT_ID` (`HOME_PARTICIPANT_ID`),
  KEY `AWAY_PARTICIPANT_ID` (`AWAY_PARTICIPANT_ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

-- --------------------------------------------------------

--
-- Table structure for table `GROUPS`
--

CREATE TABLE IF NOT EXISTS `GROUPS` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `NAME` varchar(255) NOT NULL,
  `TOURNAMENT_ID` int(11) NOT NULL,
  PRIMARY KEY (`ID`),
  UNIQUE KEY `NAME` (`NAME`,`TOURNAMENT_ID`),
  KEY `TOURNAMENT_ID` (`TOURNAMENT_ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

-- --------------------------------------------------------

--
-- Table structure for table `PLAYER`
--

CREATE TABLE IF NOT EXISTS `PLAYER` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `NAME` varchar(255) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
  `SURNAME` varchar(255) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL,
  `CLUB` varchar(255) DEFAULT NULL,
  `USER_ID` int(11) NOT NULL,
  PRIMARY KEY (`ID`),
  KEY `USER_ID` (`USER_ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

-- --------------------------------------------------------

--
-- Table structure for table `PARTICIPANT`
--

CREATE TABLE IF NOT EXISTS `PARTICIPANT` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `POINTS` int(4) NOT NULL DEFAULT '0',
  `RANK` int(4) DEFAULT NULL,
  `GROUP_ID` int(11) NOT NULL,
  `PLAYER_ID` int(11) NOT NULL,
  `SCORE` varchar(10) NOT NULL DEFAULT '0:0',
  PRIMARY KEY (`ID`),
  KEY `PLAYER_ID` (`PLAYER_ID`),
  KEY `GROUP_ID` (`GROUP_ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; 


-- --------------------------------------------------------

--
-- Table structure for table `SEASON`
--

CREATE TABLE IF NOT EXISTS `SEASON` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `NAME` varchar(255) NOT NULL,
  PRIMARY KEY (`ID`),
  KEY `USER_ID` (`USER_ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;

-- --------------------------------------------------------

--
-- Table structure for table `TOURNAMENT`
--

CREATE TABLE IF NOT EXISTS `TOURNAMENT` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `NAME` varchar(255) NOT NULL,
  `SEASON_ID` int(11) NOT NULL,
  PRIMARY KEY (`ID`),
  KEY `SEASON_ID` (`SEASON_ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ;    


--
-- Constraints for table `GAME`
--
ALTER TABLE `GAME`
  ADD CONSTRAINT `GAME_ibfk_1` FOREIGN KEY (`HOME_PARTICIPANT_ID`) REFERENCES `PARTICIPANT` (`ID`) ON DELETE CASCADE ON UPDATE CASCADE,
  ADD CONSTRAINT `GAME_ibfk_2` FOREIGN KEY (`AWAY_PARTICIPANT_ID`) REFERENCES `PARTICIPANT` (`ID`) ON DELETE CASCADE ON UPDATE CASCADE;

--
-- Constraints for table `GROUPS`
--
ALTER TABLE `GROUPS`
  ADD CONSTRAINT `GROUPS_ibfk_1` FOREIGN KEY (`TOURNAMENT_ID`) REFERENCES `TOURNAMENT` (`ID`) ON DELETE CASCADE ON UPDATE CASCADE;  


--
-- Constraints for table `PARTICIPANT`
--
ALTER TABLE `PARTICIPANT`
  ADD CONSTRAINT `PARTICIPANT_ibfk_1` FOREIGN KEY (`GROUP_ID`) REFERENCES `GROUPS` (`ID`) ON DELETE CASCADE ON UPDATE CASCADE,
  ADD CONSTRAINT `PARTICIPANT_ibfk_2` FOREIGN KEY (`PLAYER_ID`) REFERENCES `PLAYER` (`ID`) ON DELETE CASCADE ON UPDATE CASCADE;    


--
-- Constraints for table `TOURNAMENT`
--
ALTER TABLE `TOURNAMENT`
  ADD CONSTRAINT `TOURNAMENT_ibfk_1` FOREIGN KEY (`SEASON_ID`) REFERENCES `SEASON` (`ID`) ON DELETE CASCADE ON UPDATE CASCADE;
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2 回答 2

1

如果你说你有口是心非,那么你需要重新审视你的设计。你用过增强型关系图吗?这是确保您拥有正确的数据库设计的好工具。

如果您以前没有这样做过,这是一个可以帮助您的好网站:http: //users.csc.calpoly.edu/~jdalbey/205/Lectures/HOWTO-ERD.html

于 2013-10-18T11:11:47.940 回答
-1

锦标赛只是一棵二叉树。您可以使用嵌套集或邻接列表。

于 2013-10-18T11:15:38.443 回答