0

嗨我正在尝试将数据发送到网络服务

字符串 url = " https://www.myurl.com ";

    URL urlobj =  new URL(url);
    HttpsURLConnection con = (HttpsURLConnection) urlobj.openConnection();
    con.setRequestMethod("POST");
    con.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");

    String urlParameters = GenerateUrlParameters(data);

    con.setDoOutput(true);
    con.setDoInput(true);

    Log.i("test", "hit1");

    DataOutputStream  wr = new DataOutputStream(con.getOutputStream());

    Log.i("test", "hit2");

    wr.writeBytes(urlParameters);

    wr.flush();
    wr.close();

Hit1 被击中，但在下一行中失败并且没有击中 hit2。我究竟做错了什么 ？

我的日志猫

10-18 09:17:33.302: D/gralloc_goldfish(2228): Emulator without GPU emulation detected.
10-18 09:17:33.322: W/TextLayoutCache(2228): computeValuesWithHarfbuzz -- need to force to single run
10-18 09:17:37.862: I/test(2228): hit1
10-18 09:17:37.872: D/AndroidRuntime(2228): Shutting down VM
10-18 09:17:37.872: W/dalvikvm(2228): threadid=1: thread exiting with uncaught exception (group=0x409961f8)
10-18 09:17:37.912: E/AndroidRuntime(2228): FATAL EXCEPTION: main
10-18 09:17:37.912: E/AndroidRuntime(2228): java.lang.IllegalStateException: Could not execute method of the activity
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.view.View$1.onClick(View.java:3039)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.view.View.performClick(View.java:3480)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.view.View$PerformClick.run(View.java:13983)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.os.Handler.handleCallback(Handler.java:605)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.os.Handler.dispatchMessage(Handler.java:92)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.os.Looper.loop(Looper.java:137)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.app.ActivityThread.main(ActivityThread.java:4340)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.lang.reflect.Method.invokeNative(Native Method)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.lang.reflect.Method.invoke(Method.java:511)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:784)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:551)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at dalvik.system.NativeStart.main(Native Method)
10-18 09:17:37.912: E/AndroidRuntime(2228): Caused by: java.lang.reflect.InvocationTargetException
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.lang.reflect.Method.invokeNative(Native Method)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.lang.reflect.Method.invoke(Method.java:511)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.view.View$1.onClick(View.java:3034)
10-18 09:17:37.912: E/AndroidRuntime(2228):     ... 11 more
10-18 09:17:37.912: E/AndroidRuntime(2228): Caused by: android.os.NetworkOnMainThreadException
10-18 09:17:37.912: E/AndroidRuntime(2228):     at android.os.StrictMode$AndroidBlockGuardPolicy.onNetwork(StrictMode.java:1084)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.net.InetAddress.lookupHostByName(InetAddress.java:391)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.net.InetAddress.getAllByNameImpl(InetAddress.java:242)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at java.net.InetAddress.getAllByName(InetAddress.java:220)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpConnection.<init>(HttpConnection.java:71)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpConnection.<init>(HttpConnection.java:50)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpConnection$Address.connect(HttpConnection.java:351)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpConnectionPool.get(HttpConnectionPool.java:86)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpConnection.connect(HttpConnection.java:128)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpEngine.openSocketConnection(HttpEngine.java:308)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpsURLConnectionImpl$HttpsEngine.makeSslConnection(HttpsURLConnectionImpl.java:460)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpsURLConnectionImpl$HttpsEngine.connect(HttpsURLConnectionImpl.java:432)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpEngine.sendSocketRequest(HttpEngine.java:282)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpEngine.sendRequest(HttpEngine.java:232)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpURLConnectionImpl.connect(HttpURLConnectionImpl.java:80)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpURLConnectionImpl.getOutputStream(HttpURLConnectionImpl.java:188)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at libcore.net.http.HttpsURLConnectionImpl.getOutputStream(HttpsURLConnectionImpl.java:280)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at dk.example.epaypayment.EpayHttpRequest.MakePayment(EpayHttpRequest.java:53)
10-18 09:17:37.912: E/AndroidRuntime(2228):     at dk.example.epaypayment.MainActivity.sendMessage(MainActivity.java:37)
10-18 09:17:37.912: E/AndroidRuntime(2228):     ... 14 more
10-18 09:22:38.232: I/Process(2228): Sending signal. PID: 2228 SIG: 9
4

3 回答 3

12

sendPostRequest(String username, String pass)带参数调用方法。您可以从 UI 线程调用此方法，请求将从不同的线程（AsyncTask嵌入）发送。

private void sendPostRequest(String givenUsername, String givenPassword) {

    class SendPostReqAsyncTask extends AsyncTask<String, Void, String> {

        @Override
        protected String doInBackground(String... params) {
            String paramUsername = params[0];
            String paramPassword = params[1];

            System.out.println("*** doInBackground ** paramUsername "
                + paramUsername + " paramPassword :" + paramPassword);

            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(
                "http://lib-dm.process9.com/libertydm/ValidateUserHandler.ashx");// replace with your url
            httpPost.addHeader("Content-type",
                "application/x-www-form-urlencoded");
            BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair(
                "UserId", paramUsername);  // Make your own key value pair
            BasicNameValuePair passwordBasicNameValuePAir = new BasicNameValuePair(
                "Password", paramPassword);// make your own key value pair

            // You can add more parameters like above

            List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
            nameValuePairList.add(usernameBasicNameValuePair);
            nameValuePairList.add(passwordBasicNameValuePair);

            try {
                UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(
                    nameValuePairList);
                httpPost.setEntity(urlEncodedFormEntity);

                try {
                    HttpResponse httpResponse = httpClient
                        .execute(httpPost);
                    InputStream inputStream = httpResponse.getEntity()
                        .getContent();
                    InputStreamReader inputStreamReader = new InputStreamReader(
                        inputStream);
                    BufferedReader bufferedReader = new BufferedReader(
                        inputStreamReader);
                    StringBuilder stringBuilder = new StringBuilder();
                    String bufferedStrChunk = null;
                    while ((bufferedStrChunk = bufferedReader.readLine()) != null) {
                        stringBuilder.append(bufferedStrChunk);
                    }

                    return stringBuilder.toString();

                    } catch (ClientProtocolException cpe) {
                        System.out
                            .println("First Exception coz of HttpResponese :"
                                + cpe);
                        cpe.printStackTrace();
                    } catch (IOException ioe) {
                        System.out
                            .println("Second Exception coz of HttpResponse :"
                                + ioe);
                        ioe.printStackTrace();
                    }

            } catch (UnsupportedEncodingException uee) {
                System.out
                    .println("An Exception given because of UrlEncodedFormEntity argument :"
                        + uee);
                uee.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String result) {
            super.onPostExecute(result);
        }
    }

    SendPostReqAsyncTask sendPostReqAsyncTask = new SendPostReqAsyncTask();
    sendPostReqAsyncTask.execute(givenUsername, givenPassword);
}
于 2013-10-18T09:41:15.207 回答
1

尝试实现此代码，它应该可以工作。如果你的安卓版本在 4.0 以上，那么你将不得不强制使用 Asyn Task ，这样这个 http 请求就不会在主线程上运行。否则应用程序将崩溃。如果应用程序使用 HTTPGET 或 HTTPPOST 方法并在主线程上运行，它将崩溃。Asyn TAsk 是解决方案。

   HttpClient client = new DefaultHttpClient();
    HttpResponse response;
    JSONObject json=new JSONObject();
    HttpPost post = new HttpPost(url1);

    try {
        json.put("Key","your value");
        json.put("Key", "Value");


        StringEntity stringEntity = new StringEntity(json.toString());

        stringEntity.setContentEncoding("UTF-8");
        stringEntity.setContentType("application/json");
        post.setEntity(stringEntity);

        response = client.execute(post);
        Log.e("RESPONSE", response.toString());
        String responseBody = EntityUtils
                .toString(response.getEntity());
         res= responseBody.toString();

        Log.e("RESPONSE BODY", responseBody);
于 2013-10-18T10:22:20.330 回答
0

好吧，我可以建议使用 HttpClient 以更高的抽象度来完成它。

DefaultHttpClient httpClient = null;

HttpParams my_httpParams = new BasicHttpParams();

httpClient = new DefaultHttpClient(my_httpParams);

然后发送

HttpPost httpPost = new HttpPost(stringUri);
httpPost.setHeader("Content-type", "application/x-www-form-urlencoded");
httpPost.setHeader("charset", "utf-8");

if (!TextUtils.isEmpty(someStringToSend)) {
    httpPost.setEntity(new StringEntity(someStringToSend, HTTP.UTF_8));
}

HttpResponse responsePOST = httpClient.execute(httpPost);
HttpEntity resEntity = responsePOST.getEntity();

if (resEntity != null) {
    response = EntityUtils.toString(resEntity, HTTP.UTF_8);
}

我没有测试过，但应该可以。

于 2013-10-18T09:35:02.417 回答