1

如果我有一张这样的桌子：

VALUE OWNER
--------------
test1 owner1
test2 owner1
test3 owner1
test4 owner1
test5 owner1
test1 owner2
test3 owner2
test5 owner2

如何为 owner1 带回以下内容

test2
test4

基本上我想要owner1而不是owner2的所有结果。

提前致谢

KS

4

3 回答 3

4 
select * from tablename where OWNER = 'owner1' and `value` NOT IN (
select value from tablename where OWNER = 'owner2')
于 2013-10-18T09:19:49.280 回答
2

例如：

WITH my_data AS
  (SELECT 'test1' AS value, 'owner1' AS owner FROM dual
  UNION ALL SELECT 'test2' AS value, 'owner1' AS owner FROM dual
  UNION ALL SELECT 'test3' AS value, 'owner1' AS owner FROM dual
  UNION ALL SELECT 'test4' AS value, 'owner1' AS owner FROM dual
  UNION ALL SELECT 'test5' AS value, 'owner1' AS owner FROM dual
  UNION ALL SELECT 'test1' AS value, 'owner2' AS owner FROM dual
  UNION ALL SELECT 'test3' AS value, 'owner2' AS owner FROM dual
  UNION ALL SELECT 'test5' AS value, 'owner2' AS owner FROM dual)
SELECT
    value
  FROM my_data
WHERE owner = 'owner1'
MINUS
SELECT
    value
  FROM my_data
WHERE owner = 'owner2'
;
于 2013-10-18T09:20:35.800 回答
0

从 t 中选择值 where owner = 'owner1' Minus 从 t 中选择值 where owner = 'owner2'

于 2013-10-18T09:22:34.677 回答