我正在创建一个刽子手游戏。一切正常,我已经准备好用于让游戏失败并给出-1 猜测的代码。虽然当将它添加到 else 语句时,它会重复等于单词的长度,并且它也会给出一个猜测——即使它是对的?我看不出代码有什么问题?我相信这是我猜错的代码,虽然我看不到其他方法但没有正确放置?
这是代码:
private class check implements ActionListener {
public void actionPerformed(ActionEvent ae) {
try {
// Grabs the letter from the guessField and converts it into a char
// which can be used to compare against the word.
guess = guessField.getText();
guessField.setText("");
char guess2 = guess.charAt(0);
// --------------------
// Here is the guessing logic but it's currently
// not working and you can not win since i haven't written code for
// it yet. it's not selecting all the letters. for Example if
// choosing A in a word such as Banana it only selects the first
// a--------------------------- //
String displaySecret = wordField.getText();
if (displaySecret.equals("")) {/* case for fist execution */
displaySecret = "";
for (int i = 0; i < random.length(); i++)
displaySecret += "_ ";
}
String newDisplaySecret = "";
for (int v = 0; v < random.length(); v++) {
if (guess2 == random.charAt(v)) {
newDisplaySecret += random.charAt(v); // newly guessed
// character
} else {
newDisplaySecret += displaySecret.charAt(v); // old state
guesses--;
statusLabel.setText("Guesses left: " + guesses);
missField.setText(missField.getText() + guess);
if (guesses <= 0) {
JOptionPane.showMessageDialog(null,
"Game over! The word was: " + random);
guessField.setEditable(false);
wordField.setText("");
missField.setText("");
guesses = 7;
statusLabel.setText("Guesses left: " + guesses);
}
}
}
displaySecret = new String(newDisplaySecret);
wordField.setText(displaySecret);
if (displaySecret.equals(random)) {
JOptionPane.showMessageDialog(null, "You Won! The Word was: "
+ random);
guesses = 7;
statusLabel.setText("Guesses left: " + guesses);
wordField.setText("");
missField.setText("");
guessField.setEditable(false);
}
} catch (Exception e) {
System.out.println(e);
}
}
}