php - 计算值的出现并将它们打印出来

Question

我知道在阅读许多答案之前已经涵盖了这个问题，它们都告诉我如何编写 SQL，但没有告诉我如何打印结果。

我的困境是我有一个带有付款方式字段的订单表，看起来像这样

OrderID     OrderNumber     PaymentMethod
 1234         a1b2c3          PayPal
 1235         a1b2c4          Account
 1236         a1b2c5          Account
 1237         a1b2c6          PayPal
 1238         a1b2c7          Account
 1239         a1b2c8          PayPal
 1230         a1b2c9          PayPal

我需要打印出类似的东西

贝宝付款次数：4

账户支付次数：3

我试图使用这个答案

MySQL：计算不同值的出现次数

我有这个代码

SELECT PaymentMethod,COUNT(*) as Payment FROM tablename GROUP BY PaymentMethod ORDER BY Payment DESC;

但是我该如何打印出来呢？

Answer 1

$returned = mysqli_query("SELECT PaymentMethod,COUNT(distinct PaymentMethod) as Payment FROM tablename GROUP BY PaymentMethod ORDER BY Payment DESC;");
while($data = mysqli_fetch_assoc($returned)){
    echo "Number of " . $data['PaymentMethod'] . ": " . $data[0] . "<br>";
}

Answer 2

您应该将数据表示留给 VIEW。

话虽如此，这就是您可以使用纯 MySQL 提取以这种方式格式化的数据的方法：

SELECT concat('Number of ', paymentmethod ,' payments: ', count(*)) RESULT FROM t
GROUP BY paymentmethod
ORDER BY paymentmethod DESC

这导致：

|                        RESULT |
|-------------------------------|
|  Number of PayPal payments: 4 |
| Number of Account payments: 3 |

在这里拉小提琴。