1

有没有办法做这样的事情？将游标获取的数据输出到引用游标中而不先将其填充到表中？

create or replace procedure someprocedure
(
rc1 in out adv_refcur_pkg.rc)  -- this is defined below
as

v_class_year varchar(10);

cursor c1
is
select distinct e.pref_class_year
from entity e
where e.pref_class_year between i_start_class and i_end_class;

begin
open c1;
loop
fetch c1 into v_class_year;
EXIT WHEN c1%NOTFOUND;

end loop;
close c1;

open rc1 for select v_class_year from dual;
end;

这是 refcursor 的声明

CREATE OR REPLACE PACKAGE ADVANCE.adv_refcur_pkg
AS
TYPE RC IS REF CURSOR;
END adv_refcur_pkg;
4

2 回答 2

1

根据这个例子，是的，有可能：

https://forums.oracle.com/thread/696634

于 2013-10-17T13:31:56.133 回答
0

当您可以简单地传递光标本身时，为什么还要麻烦这样做呢？

create or replace procedure someprocedure
(
rc1 in out adv_refcur_pkg.rc)  -- this is defined below
as
begin
open rc1 for
   select distinct e.pref_class_year
     from entity e
    where e.pref_class_year between i_start_class and i_end_class;
end;

当您调用“someprocedure”时，您有一个打开的游标，您可以从中获取：

BEGIN
...
  someprocedure(TheCursor);
  LOOP
    fetch TheCursor into v_class_year;
    exit when TheCursor%NOTFOUND;
    ...
  END LOOP;
  CLOSE TheCursor;
...
END;
于 2013-10-17T13:51:08.320 回答