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下表是模拟来说明我遇到问题的情况：

master: code | ord
sub: code | status

我想使用连接上的 'in' 表达式更新 'sub' 行子集中的字段，如下所示：

create table master (code text, ord integer);
insert into master (code, ord) values
    ('111', 4),
    ('222', 3),
    ('333', 1),
    ('444', 2),
    ('555', 0),
    ('666', 5);

create table sub (code text, status char default 'a');
insert into sub (code) values
    ('111'),
    ('222'),
    ('333'),
    ('444'),
    ('555'),
    ('666');

update sub set status='b' where code in (select sub.code from sub inner join master 
    on sub.code=master.code where sub.status='a' order by master.ord limit 3);

所以上面看起来工作正常，但我真正想要的是对两列连接的表应用相同的操作，如：

create table master (code1 text, code2 text, ord integer);
insert into master (code1, code2, ord) values
    ('111', 'one', 4),
    ('222', 'two', 3),
    ('333', 'three', 1),
    ('444', 'four', 2),
    ('555', 'five', 0),
    ('666', 'six', 5);

create table sub (code1 text, code2 text, status char default 'a');
insert into sub (code1, code2) values
    ('111', 'one'),
    ('222', 'two'),
    ('333', 'three'),
    ('444', 'four'),
    ('555', 'five'),
    ('666', 'six');

update sub set status='b' where code1, code2 in (select 
    sub.code1, sub.code2 from sub inner join master on sub.code1=master.code1 and 
    sub.code2=master.code2 where sub.status='a' order by master.ord limit 3);

>>>
Error: near ",": syntax error

如何执行此操作？

4

1 回答 1

0

您不能将多个列（元组）与IN.

您可以使用ROWID, 代替：

update sub set status='b' where ROWID in (
    select sub.ROWID from sub inner join master on sub.code1=master.code1 and 
    sub.code2=master.code2 where sub.status='a' order by master.ord limit 3
 );
于 2013-10-17T07:47:13.773 回答