我想用 xmlhttprequest 在我的方法中实现我的onchange
方法(在我的情况下,禁止使用 jquery)。select option
这是我的select option
代码:
<tr><td>
<form name="group" id="form1">
<select name="group" id="group" onchange="member();">
<option value="" disabled selected>Choose your group..</option>
<?php foreach ($userGroups['data'] as $groups) {
echo "<option value=\"".$groups['id']."\">".$groups['name']."</option>";
}?>
</select>
</form>
</td></tr>
<tr><td id="fetchmember">
<!-- I HAVE NO IDEA WHAT CODE THAT I SHOULD WRITE HERE -->
</td></tr>
处理输入的 PHP 代码( fetchmember.php
)
<?php
include 'facebookauth.php';
$groupId = $_GET['group'];
$groupmember = $facebook->api('/'.$groupId.'/members');
$membergroup = $groupmember['data'];
foreach ($membergroup as $membergroups) {
echo "<li>".$membergroups['name']."</li>";
}
?>
来自所选组( )之一的数组结果$membergroup
:
Array ( [0] =>
Array ( [name] => Oryza NurFa
[administrator] =>
[id] => 1645819602 )
[1] =>
Array ( [name] => Muhammad Lathif Pambudi
[administrator] =>
[id] => 100000251643877 )
[2] =>
Array ( [name] => Novantio Bangun
[administrator] =>
[id] => 1152078197 )
[3] =>
Array ( [name] => Oliver Jordan
[administrator] =>
[id] => 1065251285 )
[4] =>
Array ( [name] => Fauzan Sandy
[administrator] =>
[id] => 1434833113 )
[5] =>
Array ( [name] => Arfan Fudyartanto D. N
[administrator] => 1
[id] => 1708602453 ) )
Javascript
<script type="text/javascript">
function member(str)
{
if (str==0)
{
document.getElementById("fetchmember").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("fetchmember").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","fetchmember.php?group="+str,true);
xmlhttp.send();
}
</script>
我得到的数据是一个数组。每次select
更改选项(onchange
)时,我希望脚本自动加载fetchmember.php
并打印$membergroups['name']
(来自所选 facebook 组的成员姓名)。是否可以直接检索数组数据?我认为数组必须转换为XML/JSON
. 我不知道该怎么做。我知道我的代码还是有很多不足的,无论是php,html还是js。
请帮忙。任何建议将不胜感激。谢谢