2

BD Wordpress - 表：wp_term_relationships

object_id | term_taxonomy_id| term_order
    1 | 23 | 0
    2 | 22 | 0
    3 | 23 | 0
    4 | 22 | 0
    5 | 23 | 0
    6 | 21 | 0

我需要计算每个“类别”中有多少“产品”，并在“term_order”列中插入

例如：

object_id | term_taxonomy_id| term_order
    1 | 23 | 3
    2 | 22 | 2
    3 | 23 | 3
    4 | 22 | 2
    5 | 23 | 3
    6 | 21 | 1

我做了这样的事情，但它没有更新字段“term_order”：

UPDATE `letras`.`wp_term_relationships`
SET `term_order` = '2'
WHERE `wp_term_relationships`.`object_id` = '5' ;

SELECT  object_id as id_objeto, 
        COUNT(  `object_id` ) quantidade
FROM wp_term_relationships
WHERE `object_id` =  `object_id` 
GROUP BY  `term_taxonomy_id`
4

2 回答 2

0

对不起！

我在 phpMyAdmin 中执行：

更新
设置 term_order = t2.cnt
从 wp_term_relationships t
  加入 （
    选择 term_taxonomy_id, count(*) cnt
    来自 wp_term_relationships
    按 term_taxonomy_id 分组
) t2 上 t.term_taxonomy_id = t2.term_taxonomy_id;

错误：

1064 - 您的 SQL 语法有错误；检查与您的 MySQL 服务器版本相对应的手册，以在第 3 行的“from wp_term_relationships t join (select term_taxonomy_id, count(*) cn”附近使用正确的语法

于 2013-10-17T12:37:21.673 回答
0

您可以使用子查询将表连接到自身：

update t
set term_order = t2.cnt
from wp_term_relationships t
  join (
    select term_taxonomy_id, count(*) cnt
    from wp_term_relationships
    group by term_taxonomy_id
) t2 on t.term_taxonomy_id = t2.term_taxonomy_id;

由于您使用的是 MySQL，因此应该可以：

update wp_term_relationships 
  join (
    select term_taxonomy_id, count(*) cnt
    from wp_term_relationships
    group by term_taxonomy_id
) t2 on wp_term_relationships.term_taxonomy_id = t2.term_taxonomy_id
set wp_term_relationships.term_order = t2.cnt;
于 2013-10-16T20:41:58.427 回答