0

我希望程序接受操作符号（+、-、*、/）作为输入。每当我这样做时，它都会引发异常。谁能帮我解决这个问题并让程序接受这些标志之一作为输入。

import java.lang.*;
import java.util.*;

public class Calculator
{
    private double solution;
    private static double x, y;
    private static char ops;

    public static interface Calculate
    {
        public abstract double operation(double x, double y);
    }

    public static class addition implements Calculate
    {
       public double operation(double x, double y){
         return(x+y);
       }
    }

    public static class subtraction implements Calculate
    {
       public double operation(double x, double y){
         return(x-y);
       }
    }

    public static class multiplication implements Calculate
    {
       public double operation(double x, double y){
         return(x*y);
       }
    }

    public static class division implements Calculate
    {
       public double operation(double x, double y){
         return(x/y);
       }
  }

    public void calc(int ops){
         Scanner operands = new Scanner(System.in);

         System.out.println("operand 1: ");
         x = operands.nextDouble();
         System.out.println("operand 2: ");
         y = operands.nextDouble();

         System.out.println("Solution: ");

         Calculate [] jumpTable = new Calculate[4];
         jumpTable['+'] = new addition();
         jumpTable['-'] = new subtraction();
         jumpTable['*'] = new multiplication();
         jumpTable['/'] = new division();

         solution = jumpTable[ops].operation(x, y);

         System.out.println(solution);
    }

    public static void main (String[] args)
    {
      System.out.println("What operation? ('+', '-', '*', '/')");
      System.out.println(" Enter 0 for Addition");
      System.out.println(" Enter 1 for Subtraction");
      System.out.println(" Enter 2 for Multiplication");
      System.out.println(" Enter 3 for Division");

      Scanner operation = new Scanner(System.in);
      ops = operation.next().charAt(0);

      Calculator calc = new Calculator();
      calc.calc(ops);
  }
}

错误是

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 43
at Calculator.calc(Calculator.java:54)
at Calculator.main(Calculator.java:76)
4

2 回答 2

1 
jumpTable['+']

将被转换为+符号的 ASCII 代码 (43)（它被转换为 a char），留下一个 0-4 范围之外的数字。您可能想要使用实际的数字索引（或确保您的数组可以包含您的一组 char 值的最高数字表示，在本例中为 47 by /）。

ASCII表：

在此处输入图像描述

于 2013-10-16T19:33:47.810 回答
0

您只能参考jumpTable0..3 个索引。但是您试图通过超出此范围的“+”号来引用它。考虑用HashMap<String, Calculate>这种方式存储操作：

Map<String, Calculate> jumpTable = new HashMap<String, Calculate>();
jumpTable.put("+", new addition());
jumpTable.put("-", new subtraction());
jumpTable.put("*", new multiplication());
jumpTable.put("/", new division());

String operation = Character.toString((char) ops);
solution = jumpTable.get(operation).operation(x, y);
于 2013-10-16T19:35:48.783 回答