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以前，以下查询受限于 work_category_id。事实证明，我们需要来自另一个 work_category_id 的子类的信息，所以现在我限制了 job_code_id。Job_code_id 29 是 work_category_id 88，显示的所有其他 job_code_id 是 work_category_id 36。

我需要每个job_code_ids的小时数和性能，但特别是对于'cases_per_hr'计算，我只想将cases除以job_code_id 29之外的所有小时数。我尝试了一个嵌套的case，但这似乎没有很有意义。请帮忙！

SELECT
d.user_id as 'employee_ID', 
round((sum(d.goal_hours)/sum(d.worked_hours)),2)*100 as 'performance', 
round(sum(d.goal_hours),2) as 'goal_hrs',
round(sum(d.worked_hours),2) as 'hrs_worked',
sum(d.cases) as 'total_cases_slctd', 
round(sum(d.cases)/sum(d.worked_hours),0) as 'cases_per_hr',
d.metric_dt

FROM
roster r,
prod_detail d

WHERE
d.process_level = r.process_level
and d.accounting_unit = r.accounting_unit
and d.job_code_id in ('29','322','304','303','302','305','181')
-- and d.work_category_id in('36')
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1 回答 1

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如果您只想从您的 case_per_hr 计算中排除 job_code_id = '29'，您可以执行以下操作。它确实使用 CASE WHEN。

SELECT  d.user_id as 'employee_ID', 
        round((sum(d.goal_hours)/sum(d.worked_hours)),2)*100 as 'performance', 
        round(sum(d.goal_hours),2) as 'goal_hrs',
        round(sum(d.worked_hours),2) as 'hrs_worked',
        sum(d.cases) as 'total_cases_slctd', 
        round(
              sum(CASE WHEN d.job_code_id <> '29' THEN d.cases ELSE 0 END) 
              /
              sum(CASE WHEN d.job_code_id <> '29' THEN d.worked_hours ELSE 0 END)
             ,0) as 'cases_per_hr',
        d.metric_dt

FROM    roster r,
        prod_detail d

WHERE
        d.process_level = r.process_level
        and d.accounting_unit = r.accounting_unit
        and d.job_code_id in ('29','322','304','303','302','305','181')
于 2013-10-16T18:41:12.703 回答