14

我正在尝试创建自定义格式来显示经过的时间。

现在我正在使用:

CharSequence relativeTimeSpan = DateUtils.getRelativeTimeSpanString(
     dateObject.getTime(), 
     System.currentTimeMillis(), 
     DateUtils.SECOND_IN_MILLIS,
     flags);

这将返回相对时间跨度,如下所示:

  • 1 分钟前
  • 36 分钟前
  • 4 小时前

...

我想要做的是显示这个,像这样:

  • 1m
  • 36m
  • 4小时

...

我知道 DateUtils 有 FORMAT_ABBREV_ALL 标志,但这并没有像我想要的那样缩写字符串......

我怎样才能为此创建一些自定义的东西?

4

3 回答 3

9

我已经在我的推特模块中做到了这一点

public static String getTimeString(Date fromdate) {

    long then;
    then = fromdate.getTime();
    Date date = new Date(then);

    StringBuffer dateStr = new StringBuffer();

    Calendar calendar = Calendar.getInstance();
    calendar.setTime(date);
    Calendar now = Calendar.getInstance();

    int days = daysBetween(calendar.getTime(), now.getTime());
    int minutes = hoursBetween(calendar.getTime(), now.getTime());
    int hours = minutes / 60;
    if (days == 0) {

        int second = minuteBetween(calendar.getTime(), now.getTime());
        if (minutes > 60) {

            if (hours >= 1 && hours <= 24) {
                dateStr.append(hours).append("h");
            }

        } else {

            if (second <= 10) {
                dateStr.append("Now");
            } else if (second > 10 && second <= 30) {
                dateStr.append("few seconds ago");
            } else if (second > 30 && second <= 60) {
                dateStr.append(second).append("s");
            } else if (second >= 60 && minutes <= 60) {
                dateStr.append(minutes).append("m");
            }
        }
    } else

    if (hours > 24 && days <= 7) {
        dateStr.append(days).append("d");
    } else {
        dateStr.append(twtimeformat.format(date));
    }

    return dateStr.toString();
}

public static int minuteBetween(Date d1, Date d2) {
    return (int) ((d2.getTime() - d1.getTime()) / DateUtils.SECOND_IN_MILLIS);
}

public static int hoursBetween(Date d1, Date d2) {
    return (int) ((d2.getTime() - d1.getTime()) / DateUtils.MINUTE_IN_MILLIS);
}

public static int daysBetween(Date d1, Date d2) {
    return (int) ((d2.getTime() - d1.getTime()) / DateUtils.DAY_IN_MILLIS);
}
于 2014-06-21T08:26:46.203 回答
3

像这样创建一种获取日期差异的方法

public static String getDateDifferenceForDisplay(Date inputdate) {
    Calendar now = Calendar.getInstance();
    Calendar then = Calendar.getInstance();

    now.setTime(new Date());
    then.setTime(inputdate);

    // Get the represented date in milliseconds
    long nowMs = now.getTimeInMillis();
    long thenMs = then.getTimeInMillis();

    // Calculate difference in milliseconds
    long diff = nowMs - thenMs;

    // Calculate difference in seconds
    long diffMinutes = diff / (60 * 1000);
    long diffHours = diff / (60 * 60 * 1000);
    long diffDays = diff / (24 * 60 * 60 * 1000);

    if (diffMinutes < 60) {
        return diffMinutes + " m";

    } else if (diffHours < 24) {
        return diffHours + " h";

    } else if (diffDays < 7) {
        return diffDays + " d";

    } else {

        SimpleDateFormat todate = new SimpleDateFormat("MMM dd",
                Locale.ENGLISH);

        return todate.format(inputdate);
    }
} 

然后你可以这样称呼它

String dateForDisplay = getDateDifferenceForDisplay(inputDate);
于 2014-03-31T10:09:34.767 回答
1

没有内置的方法/实用程序,但使用可用DateUtils常量实现一个非常简单:

private static final String ABBR_YEAR = "y";
private static final String ABBR_WEEK = "w";
private static final String ABBR_DAY = "d";
private static final String ABBR_HOUR = "h";
private static final String ABBR_MINUTE = "m";

public static String getAbbreviatedTimeSpan(long timeMillis) {
    long span = Math.max(System.currentTimeMillis() - timeMillis, 0);
    if (span >= DateUtils.YEAR_IN_MILLIS) {
        return (span / DateUtils.YEAR_IN_MILLIS) + ABBR_YEAR;
    }
    if (span >= DateUtils.WEEK_IN_MILLIS) {
        return (span / DateUtils.WEEK_IN_MILLIS) + ABBR_WEEK;
    }
    if (span >= DateUtils.DAY_IN_MILLIS) {
        return (span / DateUtils.DAY_IN_MILLIS) + ABBR_DAY;
    }
    if (span >= DateUtils.HOUR_IN_MILLIS) {
        return (span / DateUtils.HOUR_IN_MILLIS) + ABBR_HOUR;
    }
    return (span / DateUtils.MINUTE_IN_MILLIS) + ABBR_MINUTE;
}
于 2015-10-06T02:23:25.950 回答