我必须制作一个可以读取 .txt 文件的程序。在这个 .txt 文件中，测量了传感器上的激光束，传感器前面有一个挡住光束的刀片。慢慢地，这个刀片下降，正在测量光强度。我必须制作一个程序，用 txt 文件中的测量值计算激光束的宽度（给出公式，（（（0,9*max）-（0,1*max））/1,28 ）。
但是，如果我在没有功能的情况下这样做，它就可以正常工作。但是对这个程序有一些要求。我必须使用功能。你可能会认为我的程序有点曲折，但这主要是因为我必须这样做。如果有什么令人困惑的地方，请向我寻求更多解释，我会马上给你。
这是我目前的程序：
#include <stdio.h>
#define ROW 45
#define COLUMN 2
FILE *measurements;
float x,width, intensity, a[ROW][COLUMN]={0}, total_2 = 0, maximum = 0;
float max = 0, min = 0, difference_1 = 0, difference_2 = 0, w = 0;
float background=0, amount=0, total_1=0;
int menu=0, check_1 = 0, check_2 = 0, min_2 = 0, max_2 = 0;
//Functions
float background_radiation(float a[ROW][COLUMN]);
float average_maximum(float a[ROW][COLUMN]);
float beam_width(float a[ROW][COLUMN], float maximum);
//Integers for loops
int i = 0, r = 0, k = 0, d = 0;
main()
{
measurements = fopen("PATH\\TO\\TEXT\\FILE\\.txt", "r");
rewind(measurements);
//Menu
printf("Menu: \n\n");
printf("1. Calculate background_radiation: \n");
printf("2. Calculate average maximum signal: \n");
printf("3. Calculate beam width: \n");
printf("4. All measurements: \n");
printf("5. Quit \n\n");
printf("\nChoose:\n");
scanf("%d", &menu);
rewind(measurements);
//All data in array
while(!feof(measurements))
{
for(i=0; i<45; i++)
{
fscanf(measurements, "%f%f", &a[i][0], &a[i][1]);
}
}
//Menu loop
while (menu!=5)
{
switch(menu)
{
case 1: printf("\n------ background_radiation ------ \n");
//case check
check_1 = 1;
x= background_radiation(a);
for(i=0; i<45; i=i+1)
{
a[i][1]=a[i][1]-x;
}
break;
case 2: printf("\n------ Maximale signaal ------ \n");
//case check
check_2 = 1;
y = average_maximum(a);
break;
case 3: printf("\n------ beam_width ------ \n");
//check if the cases 1 and 2 are used
if(check_1 == 1 && check_2 == 1)
{
z = beam_width(a, y);
}
else
{
//If case 1 and 2 aren't used
printf("The backgroundradiation and maximum output aren't calculated\n");
printf("You have 2 options:\n");
printf("1. Use the first and last measurements to calculate the beamwidth.\n");
printf("2. Choose an other option of the menu.\n");
scanf("%d", &d);
//Print the beam width
if(d==1)
{
printf("\nBeamwidth:\t%f mm", ((a[0][44]-a[0][0])/1.28));
}
}
break;
case 4: printf("\n------------ Measurements ------------\n\n");
rewind(measurements);
while(!feof(measurements))
{
fscanf(measurements, "%f%f", &a[i][0], &a[i][1]);
printf("\t%2.2f mm\t\t%2.2f V\n", a[i][0], a[i][1]);
}
break;
}
rewind(measurements);
printf("\n\nChoose an option: ");
scanf("%d", &menu);
}
fclose(measurements);
return 0;
fflush(stdin);
}
float background_radiation(float a[ROW][COLUMN])
{
printf("\nHow many numbers would you like to take an average?\n");
scanf("%d", &amount);
for(i=0; i<amount; i++)
{
total_1 = total_1 + a[i][1];
}
//Calculate average
background = total_1 / amount;
printf("\nThe average background_radiation:\n%2.2f\n", background);
return(background);
}
float average_maximum(float a[ROW][COLUMN])
{
printf("\nHow many numbers would you like to take an average?\n");
scanf("%d", &amount);
for(i=44; i>(44-amount); i--)
{
total_2 = total_2 + a[i][1];
}
//Calculate average
maximum = total_2 / amount;
printf("\nAverage maxixum signal:\n%2.2f\n", maximum);
return(maximum);
}
float beam_width(float a[ROW][COLUMN], float y)
{
max = 0.9 * y;
min = 0.1 * y;
//Find a point in array
for(r=0; r<45; r++)
{
difference_1 = max - a[r][1];
if ((difference_1 < difference_2) && difference_1 > 0)
{
max_2 = r;
}
difference_2 = difference_1;
}
difference_2 = 100;
for(k=0; k<45; k++)
{
difference_1 = min - a[k][1];
if (difference_1 < difference_2 && difference_1>0)
{
min_2 = k;
}
difference_2 = difference_1;
}
//calculate width with the given formula
w = (a[max_2][0] - a[min_2][0]) / 1.28;
printf("\nBeamwidth:\t%2.2f", w);
return(w);
}
文本文件由两列和 45 行组成。第一列是刀片向下的高度。所以如果它为0。这意味着刀片完全阻挡了光束。第二列是光强度。由于传感器周围的光线（背景辐射），它总是有一个值。这是文本文件：
0.00 0.25
0.10 0.20
0.20 0.18
0.30 0.21
0.40 0.23
0.50 0.30
0.60 0.30
0.70 0.40
0.80 0.50
0.90 0.80
1.00 1.30
1.10 1.80
1.20 2.30
1.30 3.80
1.40 4.50
1.50 6.30
1.60 8.04
1.70 10.55
1.80 13.10
1.90 16.20
2.00 19.80
2.10 22.56
2.20 25.10
2.30 29.90
2.40 31.20
2.50 33.44
2.60 36.80
2.70 41.05
2.80 40.83
2.90 43.40
3.00 44.44
3.10 44.90
3.20 45.40
3.30 46.00
3.40 46.30
3.50 46.50
3.60 46.60
3.70 46.50
3.80 46.35
3.90 46.40
4.00 46.60
4.10 46.30
4.20 46.00
4.30 45.90
4.40 46.00
您可能会认为第二列在开始时下降很奇怪，但这与测量的准确性有关。
非常感谢！
什么不起作用？：
所有功能（background_radiation、average_maximum、beam_width）都不起作用。
案例 1 的输出是（始终）：
1.#J
案例 2 的输出（始终）：
0.00
如果使用案例 1 和 2
，案例 3 的输出：
0.00
否则
工作正常