6

如何在没有外键和不同名称的列的旧数据库上创建 HasMany 关系?我知道如何使用引用在 HeaderVersion 上创建一对一关系,但不知道如何创建从 Header 1 到 * HeaderVersion 的 HasMany。加入条件应为:

Header.Id1 = HeaderVersion.PId1 AND Header.Id2 = HeaderVersion.PId2

模型

领域:

public class Header {
    public virtual int Id1 { get; set; }
    public virtual int Id2 { get; set; }
    public virtual string Something { get; set; }
}

public class HeaderVersion {
    public virtual int PId1 { get; set; }
    public virtual int PId2 { get; set; }
    public virtual int Version { get; set; }
    public virtual string SomethingFoo { get; set; }
}

地图:

 public HeaderMap() {
        Table("Header");
        LazyLoad();
        CompositeId().KeyProperty(x => x.Id1, "Id1")
                     .KeyProperty(x => x.Id2, "Id2");
        Map(x => x.Something).Column("Something");
 }

 public HeaderVersionMap() {
        Table("HeaderVersion");
        LazyLoad();
        CompositeId().KeyProperty(x => x.PId1, "PId1")
                     .KeyProperty(x => x.PId2, "PId2")
                     .KeyProperty(x => x.Version, "Version");
        Map(x => x.SomethingFoo).Column("SomethingFoo");
 }
4

1 回答 1

5

假设Header是(省略了GetHashCode和的覆盖Equals

public class Header
{
    public virtual int Id1 { get; set; }
    public virtual int Id2 { get; set; }
    public virtual string Something { get; set; }
    public virtual ICollection<HeaderVersion> Versions { get; set; }
}

HeaderMap应该看起来像:

public class HeaderMap : ClassMap<Header>
{
    public HeaderMap()
    {
        Table("Header");
        LazyLoad();
        CompositeId().KeyProperty(x => x.Id1, "Id1")
                     .KeyProperty(x => x.Id2, "Id2");
        Map(x => x.Something).Column("Something");
        HasMany(x => x.Versions).AsBag().KeyColumns.Add("PId1", "PId2");
        // Fetch, Inverse, Cascade depend on your mapping strategy
    }
}
于 2013-10-16T13:36:01.697 回答