python - 数组的非零子序列

Question

我正在尝试编写代码来获取这种形式的列表的子序列：

l = [240,200,160,4,0,0,0,0,4,4,4,0,0,0,1,1,1,1]

基本上，我需要得到不为零的子序列，所以我需要这种形式的输出：

output = [[255,200,160,4] , [4,4,4] , [1,1,1,1]]

谢谢你。

Answer 1

连续子序列？寻呼 Dr. Groupby, Dr. itertools.groupby:

>>> from itertools import groupby
>>> l = [240,200,160,4,0,0,0,0,4,4,4,0,0,0,1,1,1,1]
>>> [list(g) for k,g in groupby(l, lambda x: x != 0) if k]
[[240, 200, 160, 4], [4, 4, 4], [1, 1, 1, 1]]

或者即使我们利用事实bool(0)isFalse和bool(any other integer)is True：

>>> [list(g) for k,g in groupby(l, bool) if k]
[[240, 200, 160, 4], [4, 4, 4], [1, 1, 1, 1]]

Answer 2

In [117]: l = [240,200,160,4,0,0,0,0,4,4,4,0,0,0,1,1,1,1]

In [118]: [list(vals) for mask,vals in itertools.groupby(l, key=lambda n:n!=0) if mask]
Out[118]: [[240, 200, 160, 4], [4, 4, 4], [1, 1, 1, 1]]