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我正在制作一个几乎完成的 C++ Mind Reader 程序。但是，感觉有必要跳过第二个cin。我已经搜索过，我不确定是什么问题。我检查了代码，我敢打赌我做了一些愚蠢的事情，但我仍然对此感到困惑。跳过的 cin 在第 32 行，这是我的代码：

#include <iostream>
#include <string>
#include <cstdlib>

using namespace std;

int main()
{
    //declaring variables to be used later
    string name;
    string country;
    int age;

    //header goes below
    cout << "                     @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@\n\n";

    //asks if the user would like to continue and in not, terminates
    cout << "Would like you to have your mind read? Enter y for yes and n for no." << endl;
    cout << "If you do not choose to proceed, this program will terminate." << endl;
    string exitOrNot;
    //receives user's input
    cin >> exitOrNot;
    //deals with input if it is 'y'
    if (exitOrNot == "y"){
        cout << "Okay, first you will need to sync your mind with this program. You will have to answer the following questions to synchronise.\n\n";

        //asks questions
        cout << "Firstly, please enter your full name, with correct capitalisation:\n\n";
        cin >> name;

        cout << "Now please enter the country you are in at the moment:\n\n";
        cin >> country; //<------ Line 32

        cout << "This will be the final question; please provide your age:\n\n";
        cin >> age;

        //asks the user to start the sync
        cout << "There is enough information to start synchronisation. Enter p to start the sync...\n\n";
        string proceed;
        cin >> proceed;
        //checks to see if to proceed and does so
        if (proceed == "p"){
            //provides results of mind read
            cout << "Sync complete." << endl;
            cout << "Your mind has been synced and read.\n\n";
            cout << "However, due to too much interference, only limited data was aquired from your mind." << endl;
            cout << "Here is what was read from your mind:\n\n";

            //puts variables in sentence
            cout << "Your name is " << name << " and you are " << age << " years old. You are based in " << country << "." << endl << "\n\n";

            cout << "Thanks for using Mind Reader, have a nice day. Enter e to exit." << endl;
            //terminates the program the program
            string terminate;
            cin >> terminate;
            if (terminate == "e"){
                exit(0);
            }

        }

    }
    //terminates the program if the input is 'n'
    if (exitOrNot == "n"){
        exit(0);
    }

    return 0;
}

编辑：这是我运行它时发生的情况：

                     @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@

Would like you to have your mind read? Enter y for yes and n for no.
If you do not choose to proceed, this program will terminate.
y
Okay, first you will need to sync your mind with this program. You will have to
answer the following questions to synchronise.

Firstly, please enter your full name, with correct capitalisation:

John Smith
Now please enter the country you are in at the moment:

This will be the final question; please provide your age:

13
There is enough information to start synchronisation. Enter p to start the sync.
..

p
Sync complete.
Your mind has been synced and read.

However, due to too much interference, only limited data was aquired from your m
ind.
Here is what was read from your mind:

Your name is John and you are 13 years old. You are based in Smith.


Thanks for using Mind Reader, have a nice day. Enter e to exit.
e

Process returned 0 (0x0)   execution time : 78.220 s
Press any key to continue.

为了更清楚，这里有一个截图：http: //puu.sh/4QZb3.png 我不能在这篇文章中附加它，因为我没有足够的代表。

还值得注意的是它如何使用用户的姓氏作为国家。我相信问题与输入不是整数有关。

谢谢。

4

4 回答 4

5

您只能将一个单词输入到cin. 相反，使用getline(cin, string name);如果它仍然不起作用，cin.ignore();请在您的 之前添加一个getline(cin, string name);，如下所示：

string country;
cout << "Now please enter the country you are in at the moment:\n\n";
cin.ignore();
getline(cin, country);

这现在肯定会奏效。

于 2014-06-24T00:53:36.570 回答
3

问题是您正在使用：cin >>从用户那里获取字符串。如果用户输入超过 1 个单词，则会导致代码中的行相互跳过。为了解决这个问题，我们将使用：getLine(cin,yourStringHere)从用户那里获取一个字符串。这是您的代码全部修复：

#include <iostream>
#include <string>
#include <cstdlib>

using namespace std;

int main()
{
    string name;
    string country;
    int age;
    cout << "                     @@@@@@@@@@@@-MIND READER-@@@@@@@@@@@@\n\n";

    cout << "Would like you to have your mind read? Enter y for yes and n for no." << endl;
    cout << "If you do not choose to proceed, this program will terminate." << endl;
    string exitOrNot;
    getline (cin,exitOrNot); /*<-----Changed from cin to getLine*/
    if (exitOrNot == "y"){
        cout << "Okay, first you will need to sync your mind with this program. You will have to answer the following questions to synchronise.\n\n";

        cout << "Firstly, please enter your full name, with correct capitalisation:\n\n";
        getline(cin,name); /*<--Another string*/

        cout << "Now please enter the country you are in at the moment:\n\n";
        getline(cin,country); /*<--Another string*/

        cout << "This will be the final question; please provide your age:\n\n";
        cin >> age;

        cout << "There is enough information to start synchronisation. Enter p to start the sync...\n\n";
        string proceed;
        cin >> proceed;
        if (proceed == "p"){
            cout << "Sync complete." << endl;
            cout << "Your mind has been synced and read.\n\n";
            cout << "However, due to too much interference, only limited data was aquired from your mind." << endl;
            cout << "Here is what was read from your mind:\n\n";

            cout << "Your name is " << name << " and you are " << age << " years old. You are based in " << country << "." << endl << "\n\n";

            cout << "Thanks for using Mind Reader, have a nice day. Enter e to exit." << endl;
            string terminate;
            cin >> terminate;
            if (terminate == "e"){
                exit(0);
            }

        }

    }
    if (exitOrNot == "n"){
        exit(0);
    }

    return 0;
}
于 2013-10-16T01:05:18.003 回答
0

上述用户所说，cin 只允许将 1 个单词输入到每个 cin 的字符串中。因此，我认为您想要的是： getline(cin, name)

于 2013-10-15T20:52:05.147 回答
0 
cin.get();
cout << "Now please enter the country you are in at the moment:\n\n";
cin >> country; //<------ Line 32

像我上面所做的那样在 cout 之前输入 cin.get() ，您的问题将得到解决。

于 2018-06-08T19:43:09.437 回答