2

嗨,我基本上使用 zmq 模块编写了一个客户端和一个服务器。我能够使用我的客户端向服务器发送一个普通字符串作为输入,并且数据显示良好。但是当我传递一个 JSON 对象时,它的打印方式不同。下面是我的客户代码

客户代码

var zmq = require('zmq');
// socket to talk to server
console.log("Connecting to hello world server...");
var requester = zmq.socket('req');

var x = 0;
requester.on("message", function(reply) {

console.log("Received reply for client from server", ": [", reply.toString(), ']');
x += 1;
if (x === 5) {
requester.close();
 process.exit(0);

} });

requester.connect("tcp://localhost:7000");

for (var i = 0; i < 5; i++) {

console.log("Sending request", i, '...');
requester.send({"AdvisorId" : "71864", "Phone": "952-921-4972"});
}

process.on('SIGINT', function() {
requester.close();
});

服务器代码

// Hello World server
// Binds REP socket to tcp://*:7000
// Expects "Hello" from client, replies with "world"

var zmq = require('zmq');

// socket to talk to clients
var responder = zmq.socket('rep');

responder.on('message', function(request) {

 console.log("Received request: [", request, "]");
console.log(typeof request)

 // do some 'work'
 setTimeout(function() {

// send reply back to client.
responder.send("world");
 }, 1000);
});

responder.bind('tcp://*:7000', function(err) {
if (err) {
console.log(err);
 } else {

console.log("Listening on 7000...");
 }
});

process.on('SIGINT', function() {
responder.close();
});

请求服务器中的数据

Received request: [ <SlowBuffer 5b 6f 62 6a 65 63 74 20 4f 62 6a 65 63 74 5d> ]

而我发送的数据是 {"AdvisorId" : "71864", "Phone": "952-921-4972"} 这是一个 JSON 对象。我卡在这里任何有关这方面的帮助都会很有帮助。

4

2 回答 2

3
var jsonObject={"AdvisorId" : "71864", "Phone": "952-921-4972"} ;
var stringObject=JSON.stringify(jsonObject);
requester.send(stringObject);

这将工作.. !!

于 2014-03-20T10:16:28.013 回答
0

ZeroMq 支持字符串和字节[] 数据,而不是对象。

尝试这个:

requester.send("{AdvisorId" : "71864", "Phone": "952-921-4972}");
于 2013-10-15T14:02:51.300 回答