8

我有一个MediaElement，DataTemplate但我无法从后面的代码中访问它。

我在下面发布 XAML 代码：

<Grid>
    <Grid.ColumnDefinitions>
        <ColumnDefinition Width="605*"/>
        <ColumnDefinition Width="151*"/>
    </Grid.ColumnDefinitions>
    <GroupBox Header="My Videos" Height="177" VerticalAlignment="Top" Margin="5,320,5,0" Grid.ColumnSpan="2">
        <ListBox x:Name="VideoList" ItemsSource="{Binding Videos }" Width="auto" Height=" auto" Margin="0,0,0,0" Grid.ColumnSpan="2" >
            <DataTemplate x:Name="DTVideos">
                <ListBoxItem Name="lbivid1" BorderThickness="2"  Width="240" Selected="lbivid_Selected" >
                    <MediaElement Name="vidList" Height="150" Width="150" Source="{Binding SourceUri}" Position="00:00:05" LoadedBehavior="Pause" ScrubbingEnabled="True"/>
                </ListBoxItem>
            </DataTemplate>
            <ItemsControl.ItemsPanel>
                <ItemsPanelTemplate>
                    <StackPanel Orientation="Horizontal" Margin="0,0,0,0"/>
                </ItemsPanelTemplate>
            </ItemsControl.ItemsPanel>
        </ListBox>
    </GroupBox>     
    <GroupBox Header="Preview" Height="320" Width="400" VerticalAlignment="Top" DockPanel.Dock="Left">
        <MediaElement x:Name="videoPreview" HorizontalAlignment="Left" Height="300" VerticalAlignment="Top" Width="388"/>
    </GroupBox>
</Grid>

后面的代码：

 private void lbivid_Selected(object sender, RoutedEventArgs e)
 {   
    imagePreview.Visibility = Visibility.Hidden;   
    string urlStr = (VidList.Source).ToString();          
    Uri temp = new Uri(UrlStr);
    videoPreview.Source = temp;                         
 }

你们中的任何人都可以告诉我怎么做吗？

4

2 回答 2

23

您应该能够使用该FrameworkTemplate.FindName方法访问您的控件...首先，ContentPresenter从其中一个中获取ListBoxItem：

ContentPresenter contentPresenter = FindVisualChild<ContentPresenter>(yourListBoxItem);

然后DataTemplate从ContentPresenter：

DataTemplate yourDataTemplate = contentPresenter.ContentTemplate;

然后MediaElement从DataTemplate：

MediaElement yourMediaElement = yourDataTemplate.FindName("vidList", contentPresenter) 
as MediaElement;
if (yourMediaElement != null)
{
    // Do something with yourMediaElement here
}

有关详细信息，请参阅 MSDN 上的FrameworkTemplate.FindName方法页面。

于 2013-10-15T12:12:39.783 回答
-1

您的事件处理程序中有发送者，即 ListBoxItem，而 MediaElement 是 ListBoxItem.Content

var mediaElement = ((ListBoxItem)sender).Content as MediaElement;
if (mediaElement != null) ...
于 2013-10-15T11:23:32.947 回答