在代码中,我从数据库中收集数据,然后根据数据的值更新它。我可以检索这些值,但我无法更新它们 我需要有关更新函数的语法或不同类型函数的帮助。
<?php
$con = mysqli_connect("127.0.0.1","root","","timeclock");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}else{
echo "connected";
}
$x=2;
timein($x);
function timein($x){
$con = mysqli_connect("127.0.0.1","root","","timeclock");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}else{
echo "connected";
}
$result=mysqli_query($con,"SELECT * FROM emplo`enter code here`yeedatabase WHERE employeeID=$x ORDER BY employeeID" );
while($row = mysqli_fetch_array($result))
{
$inout = $row['inOut'];
}
echo $inout;
if($inout == 1){
echo "hello";
$con = mysqli_connect("127.0.0.1","root","","timeclock");
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}else{
echo "connected";
}
$result=mysqli_query($con,"SELECT * FROM employeedatabase WHERE employeeID=$x ORDER BY employeeID" );
while($row = mysqli_fetch_array($result))
{
$inout = $row['inOut'];
$row['inOut']=2;
}
echo "</table>";
echo $inout;
$outa=2;
mysqli_query($con,"UPDATE employeedatabase SET inOut='$outa' WHERE employeeID='$x'");
}
}
?>-## Heading ##
mysqli 查询函数不工作 我需要一个新函数或更好的 mysqli 函数语法。