sql - 根据列之间的比较，将最大值的列名分配给行

Question

OID_ _ HOS1 _ _ HOS2 _ _ HOS3   
 A _ _ _ _ 3 _ _ _ _ _7 _ _ _ _10  
 B _ _ _ _ 12 _ _ _ _ 5 _ _ _ _ 8   
 C _ _ _ _ 3 _ _ _ _ 13_ _ _ _ 7  

考虑这张给定区域 (OID) 的医院就诊表。我想做的是在sql中自动确定上表的最后两列。我想比较每个地区（A、B、C）的所有医院就诊次数（HOS1、HOS2、HOS3），并为每个地区分配最高访问次数到 MAXV 列和访问次数最多的医院代码到 MAXH 列，使其如下表所示。

OID_ _ HOS1 _ _ HOS2 _ _ HOS3 _ _ MAXV _ _ MAXH  
 A _ _ _ _ 3 _ _ _ _ _ 7_ _ _ _ _ 10 _ _ _ 10 _ _ _ HOS3  
 B _ _ _ _ 12 _ _ _ _ 5 _ _ _ _ _ 8 _ _ _ _12 _ _ _ HOS1  
 C _ _ _ _ 3 _ _ _ _ 13 _ _ _ _ _ 7 _ _ _ _13 _ _ _ HOS2

Answer 1

对于 SQL Server 2005+：

SELECT T.*, C.ColValue MAXV, C.ColName MAXH
FROM YourTable T
OUTER APPLY (SELECT TOP 1 *
             FROM (SELECT 'HOS1', HOS1
                   UNION ALL
                   SELECT 'HOS2', HOS2
                   UNION ALL
                   SELECT 'HOS3', HOS3) X(ColName,ColValue)
             ORDER BY ColValue DESC) C

这是一个演示。结果如下：

╔═════╦══════╦══════╦══════╦══════╦══════╗
║ OID ║ HOS1 ║ HOS2 ║ HOS3 ║ MAXV ║ MAXH ║
╠═════╬══════╬══════╬══════╬══════╬══════╣
║ A   ║    3 ║    7 ║   10 ║   10 ║ HOS3 ║
║ B   ║   12 ║    5 ║    8 ║   12 ║ HOS1 ║
║ C   ║    3 ║   13 ║    7 ║   13 ║ HOS2 ║
╚═════╩══════╩══════╩══════╩══════╩══════╝

Answer 2

select
    t.[OID], t.[HOS1], t.[HOS2], t.[HOS3],
    c.MAXV, c.MAXH
from Table1 as t
    outer apply (
        select top 1 *
        from (values
           (HOS1, 'HOS1'),
           (HOS2, 'HOS2'),
           (HOS3, 'HOS3')
        ) as a(MAXV, MAXH)
        order by a.MAXH desc
    ) as C

sql fiddle demo