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我有一个 XML 文件，我将其读入 PHP 数组以使用 CakePHP 的 XML::toArray($xmlString) 函数进行处理。

一切正常，我可以轻松地处理数据，但是，当我尝试运行 in_array 检查时，它继续返回 false，即使我知道值在那里。

这是 if 语句：

$xmlArray = Xml::toArray($xmlString);
$menus = $xmlArray['navigation'];
$groupId = array($groupId); // Group ID of logged in user, in my case 1
$loggedInId = array($loggedInId); // User ID, in my case 182
//I change them both into arrays, as the second param needs to be an array, and in the XML file, there could only be one value, in which case it's "translated" as a string
//$submenu == foreach($menu['submenu']['menu'] as $subenu)
if(in_array($submenu['permission']['group'],$groupId) || in_array($submenu['permission']['user'],$loggedInId)) {
    //do stuff
}

这是 XML 文件（导航位）：

<?xml version="1.0" encoding="utf-8"?>
<navigation>
    <menu>
        <title>Home</title>
        <url>home</url>
        <submenus>
            <menu>
                <title>In memory of...</title>
                <url>memoriams</url>
                <image>memoriam</image>
                <permission>
                    <group>1</group>
                    <user>0</user>
                </permission>
            </menu>
            <menu>
                <title>Reports</title>
                <url>reports</url>
                <image>report</image>
                <permission>
                    <group>4</group>
                    <group>5</group>
                    <user>252</user>
                    <user>182</user>
                    <user>234</user>
                </permission>
            </menu>
        </submenus>
    </menu>
</navigation>

菜单仅在第一种情况下显示。也就是说，如果组/用户只有 1 个值。如果它有多个值，它只是不显示子菜单。

这是数组的调试：

array(
    'menu' => array(
        'title' => 'Home',
        'url' => 'home',
        'submenus' => array(
            'menu' => array(
                (int) 0 => array(
                    'title' => 'In memory of...',
                    'url' => 'memoriams',
                    'image' => 'memoriam',
                    'permission' => array(
                        'group' => '1',
                        'user' => '0'
                    )
                ),
                (int) 1 => array(
                    'title' => 'Reports',
                    'url' => 'reports',
                    'image' => 'report',
                    'permission' => array(
                        'group' => array(
                            (int) 0 => '4',
                            (int) 1 => '5'
                        ),
                        'user' => array(
                            (int) 0 => '252',
                            (int) 1 => '182',
                            (int) 2 => '234'
                        )
                    )
                )
            )
        )
    )
)

有谁知道为什么它不想工作？

4

2 回答 2

2

函数的第一个参数in_array是needle第二个参数是array搜索匹配！

参考：PHP手册

于 2013-10-14T17:54:42.223 回答
1 
foreach ($menu['menu']['submenus']['menu'] as $submenu) {
  $group = $submenu['permission']['group'];
  $user = $submenu['permission']['user'];
  if(in_array($group, (array) $groupId) || in_array($user, (array) $loggedInId)) {
    //do stuff
  }
}
于 2013-10-14T18:03:24.120 回答