我有一个问题,我想手动确定文件夹名称。例如,如果用户按以下方式运行此脚本,
./scriptname -k
他们可以获取结果,但文件夹名称是在脚本中确定的。如何手动确定文件夹名称,如下所示?
您可以将帮助编写为函数:
usage(){
cat <<EOT
Usage: ${0##*/} dir1 dir2
EOT
}
if [ $# -ne 2 ]; then
usage
echo 'please enter two folder names'
exit 1
fi
if [ ! -d "$1" ]; then
usage
echo "$1 is not a folder"
exit 1
fi
if [ ! -d "$2" ]; then
usage
echo "$2 is not a folder"
exit 1
fi
# continue script
#!/bin/bash
check_input_directories()
{
if [[ ! -f "${folder1}" "${folder2}" ]]; then
#your searching program
fi
}
Show_help()
{
cat <<_EOF
Usage : $0 <options> <path>
Options:
-f <folder> <folder>
_EOF
}
MAIN () {
case "$1" in
-f)
check_input_directories
;;
*)
Show_help
esac
}
MAIN $*
我昨天删除了一个未经测试的答案,今天用这个经过测试的 bash 脚本返回:
#!/bin/bash
check_input_directories() {
folder1="$1"
folder2="$2"
if [[ ! -d "${folder1}" && ! -d "${folder2}" ]]; then
dir1=~/${folder1}
dir2=~/${folder2}
for i in $(find $dir1 -printf "%f\n")
do
find $dir2 -name $i -print
done
fi
}
Show_help() {
cat <<_EOF
Usage : $0 <options> <path>
You can use this script as below,
-d folder1/ folder2/
_EOF
}
MAIN () {
case "$1" in
-d)
check_input_directories $2 $3
;;
*)
Show_help
esac
}
MAIN $*