sql - 返回出现超过 x 次的字段的行数

Question

在我的 SQL 表中，我想找到出现超过 300 次的状态代码，以及包含每个相应状态代码的记录的总行数。我的 SQL 有点生疏（加上星期一早上 8 点......），这就是我到目前为止所拥有的：

SELECT StateCode
FROM ZipCodeTerritory
HAVING COUNT(StateCode) > 300

Answer 1

SELECT StateCode, Count(*) As StateCodeCount
FROM ZipCodeTerritory
Group By StateCode
HAVING COUNT(*) > 300

Answer 2

像这样的东西？

SELECT StateCode, count(StateCode)
FROM ZipCodeTerritory
GROUP BY StateCode
HAVING COUNT(StateCode) > 300

Answer 3

SELECT StateCode, count(*)
FROM ZipCodeTerritory
GROUP BY StateCode
HAVING count(*) > 300