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如果我需要自己的 IList(T),但不想从头开始实现它,我可以继承自

System.Collections.ObjectModel.Collection<T>

这将允许我自定义添加、删除和清除操作。
但是如果我想要完全一样的我该怎么办

IDictionary<T1, T2> 

?

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1 回答 1

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为什么不创建一个IDictionary<TKey,TVal>将方法调用委托给内部持有的实现Dictionary<TKey,TVal>?然后你可以以任何你认为合适的方式改变行为!

public class MyCustomDictionary<TKey,TVal>:IDictionary<TKey,TVal>
{
    private Dictionary<TKey, TVal> dictionary;

    public MyCustomDictionary()
    {
        dictionary=new Dictionary<TKey, TVal>();
    }

    public void CopyTo(Array array, int index)
    {
        ((ICollection) dictionary).CopyTo(array, index);
    }

    public object SyncRoot
    {
        get { return ((ICollection) dictionary).SyncRoot; }
    }

    public bool IsSynchronized
    {
        get { return ((ICollection) dictionary).IsSynchronized; }
    }

    public bool Contains(object key)
    {
        return ((IDictionary) dictionary).Contains(key);
    }

    public void Add(object key, object value)
    {
        ((IDictionary) dictionary).Add(key, value);
    }

    public void Remove(object key)
    {
        ((IDictionary) dictionary).Remove(key);
    }

    public object this[object key]
    {
        get { return dictionary[(TKey) key]; }
        set { dictionary[(TKey) key] = (TVal) value; }
    }

    public bool IsFixedSize
    {
        get { return ((IDictionary) dictionary).IsFixedSize; }
    }

    public void Add(TKey key, TVal value)
    {
        dictionary.Add(key, value);
    }

    public void Clear()
    {
        dictionary.Clear();
    }

    public bool Contains(KeyValuePair<TKey, TVal> item)
    {
        TVal v;
        return (dictionary.TryGetValue(item.Key, out v) && v.Equals(item.Key));
    }

    public void CopyTo(KeyValuePair<TKey, TVal>[] array, int arrayIndex)
    {
        ((ICollection<KeyValuePair<TKey, TVal>>)dictionary)
            .CopyTo(array,arrayIndex);
    }

    public bool Remove(KeyValuePair<TKey, TVal> item)
    {
        if (Contains(item))
        {
            dictionary.Remove(item.Key);
            return true;
        }
        return false;
    }

    public bool ContainsKey(TKey key)
    {
        return dictionary.ContainsKey(key);
    }

    public bool ContainsValue(TVal value)
    {
        return dictionary.ContainsValue(value);
    }

    public void GetObjectData(SerializationInfo info, StreamingContext context)
    {
        dictionary.GetObjectData(info, context);
    }

    public void OnDeserialization(object sender)
    {
        dictionary.OnDeserialization(sender);
    }

    public bool Remove(TKey key)
    {
        return dictionary.Remove(key);
    }

    public bool TryGetValue(TKey key, out TVal value)
    {
        return dictionary.TryGetValue(key, out value);
    }

    public IEqualityComparer<TKey> Comparer
    {
        get { return dictionary.Comparer; }
    }

    public int Count
    {
        get { return dictionary.Count; }
    }

    public bool IsReadOnly { get; private set; }

    public TVal this[TKey key]
    {
        get { return dictionary[key]; }
        set { dictionary[key] = value; }
    }

    public ICollection<TKey> Keys
    {
        get { return dictionary.Keys; }
    }

    public ICollection<TVal> Values
    {
        get { return dictionary.Values; }
    }

    public IEnumerator<KeyValuePair<TKey, TVal>> GetEnumerator()
    {
        return dictionary.GetEnumerator();
    }

    public void Add(KeyValuePair<TKey,TVal> item)
    {
        dictionary.Add(item.Key,item.Value);
    }

    IEnumerator IEnumerable.GetEnumerator()
    {
        return GetEnumerator();
    }
}
于 2013-10-14T11:23:04.137 回答