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我正在制作 Java 纸牌游戏，现在我尝试为电脑玩家创建“大脑”。条件：

  • 桌上有3张牌（只有价值，没有花色）；

  • 电脑玩家（CP）有6张牌；

  • 赢得一局CP必须至少击败桌上的2张牌，或者
    必须击败1张牌并与另外2张牌打成平局；

  • 当然，卡组必须是最优的。

例子：桌子上有1、2、3的牌。CP有1、1、3、2、5、6的牌。它必须选择2的牌才能打败1，而不是选择3的牌击败 Card2 而不是选择价值为 1 的卡，因为它已经击败了 2 张卡。现在我编写了下一个代码，但它不能正常工作或根本不能工作。

for (i = 0, j = i++, k = j++; i < oppHand.size() - 2 && j < oppHand.size() - 1 && k < oppHand.size(); i++) {

a = oppHand.get(i).getPower(); //value of card1 from CP hand
b = oppHand.get(j).getPower(); //value of card2 from CP hand
c = oppHand.get(k).getPower(); //value of card3 from CP hand

x = oppHand.indexOf(i);        //position of card1 in a CP hand
y = oppHand.indexOf(j);        //position of card2 in a CP hand
z = oppHand.indexOf(k);        //position of card3 in a CP hand

if (a > Score1 && b > Score2 ||  a> Score1 && c > Score3) {    //Score - value of the cards on the table
choice1 = x;
choice2 = y;
choice3 = z;}

else if (a > Score1 && b > Score3 || a > Score1 && c > Score2) {
choice1 = x;
choice2 = z;
choice3 = y;} ........

// moving cards from the CP hand to the table with assignment values to the piles
    validPower5 = oppHand.get(choice1).getPower();  
    discardPile5.add(0, oppHand.get(choice1));
    oppHand.remove(choice1);

    validPower6 = oppHand.get(choice2).getPower();  
    discardPile6.add(0, oppHand.get(choice2));
    oppHand.remove(choice2);

    validPower7 = oppHand.get(choice3).getPower();  
    discardPile7.add(0, oppHand.get(choice3));
    oppHand.remove(choice3);
                    }
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2 回答 2

0

I think you if else condition need to be correct..

Not sure but check this code for that.

if (a > Score1) 
{    //Score - value of the cards on the table
    if (b > Score2 || c > Score3)   {
        choice1 = x;
        choice2 = y;
        choice3 = z;    }
    else if (b > Score3 || c > Score2)  {
        choice1 = x;
        choice2 = y;
        choice3 = z;    }
}

I think this should work ...

于 2013-10-14T09:07:19.123 回答
0

这样的事情会有帮助吗？

sortCardsOnTable();//now Score1 <= Score2 <= Score2
sortOpponentCards();
boolean beatScore1 = false;
boolean beatScore2 = false;
int indexFirst = 0;
int indexSecond = 0;
int indexThird = 0;

for(int i = 0;i < oppHand.size();i++){
   Card c = oppHand.get(i);
   if(!beatScore1 && c.getPower() > Score1){
      indexFirst = i;
      beatScore1 = true;
   }
   else if(beatScore1 && c.getPower() > Score2){
      indexSecond = i;
      beatScore2 = true;
      indexThird = 1;//here compare with indexFirst so you dont pull the first card twice, just pull the first available card
   }
}

您应该对 Cardlist 进行排序，以简化计算

于 2013-10-14T08:28:25.730 回答