在我正在做的一个项目中，我必须从结构化文件 (xml) 中获取用户输入。该文件包含一个区域的道路数据，我必须将其绘制到 matplotlib 画布上。问题是，随着道路，我还要渲染道路名称，而且大部分道路都是弯曲的。我知道如何以某个角度呈现文本。但我想知道是否可以在字符串中途更改文本角度？
像这样：在弯曲路径上绘制旋转文本
但是使用matplotlib。
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7528 次
2 回答
41
这是我对这个问题的看法：为了使文本在绘制后对图形调整具有鲁棒性，我CurvedText从matplotlib.text. 该对象采用- 和 -值数组CurvedText形式的字符串和曲线。要显示的文本本身被切割成单独的字符，每个字符都被添加到绘图的适当位置。如果字符串为空，则不会绘制任何内容，因此我将所有空格替换为不可见的“a”。调整后，重载调用该函数，该函数注意字符位置和方向保持正确。为了确保调用顺序（每个角色的函数也会被调用），对象还需要注意xymatplotlib.textfiguredraw()update_positions()draw()CurvedTextzorder每一个字都比自己高zorder。按照我的示例here，文本可以有任何对齐方式。如果文本在当前分辨率下无法适应曲线，其余部分将被隐藏，但会在调整大小时出现。下面是带有应用程序示例的代码。
from matplotlib import pyplot as plt
from matplotlib import patches
from matplotlib import text as mtext
import numpy as np
import math
class CurvedText(mtext.Text):
"""
A text object that follows an arbitrary curve.
"""
def __init__(self, x, y, text, axes, **kwargs):
super(CurvedText, self).__init__(x[0],y[0],' ', **kwargs)
axes.add_artist(self)
##saving the curve:
self.__x = x
self.__y = y
self.__zorder = self.get_zorder()
##creating the text objects
self.__Characters = []
for c in text:
if c == ' ':
##make this an invisible 'a':
t = mtext.Text(0,0,'a')
t.set_alpha(0.0)
else:
t = mtext.Text(0,0,c, **kwargs)
#resetting unnecessary arguments
t.set_ha('center')
t.set_rotation(0)
t.set_zorder(self.__zorder +1)
self.__Characters.append((c,t))
axes.add_artist(t)
##overloading some member functions, to assure correct functionality
##on update
def set_zorder(self, zorder):
super(CurvedText, self).set_zorder(zorder)
self.__zorder = self.get_zorder()
for c,t in self.__Characters:
t.set_zorder(self.__zorder+1)
def draw(self, renderer, *args, **kwargs):
"""
Overload of the Text.draw() function. Do not do
do any drawing, but update the positions and rotation
angles of self.__Characters.
"""
self.update_positions(renderer)
def update_positions(self,renderer):
"""
Update positions and rotations of the individual text elements.
"""
#preparations
##determining the aspect ratio:
##from https://stackoverflow.com/a/42014041/2454357
##data limits
xlim = self.axes.get_xlim()
ylim = self.axes.get_ylim()
## Axis size on figure
figW, figH = self.axes.get_figure().get_size_inches()
## Ratio of display units
_, _, w, h = self.axes.get_position().bounds
##final aspect ratio
aspect = ((figW * w)/(figH * h))*(ylim[1]-ylim[0])/(xlim[1]-xlim[0])
#points of the curve in figure coordinates:
x_fig,y_fig = (
np.array(l) for l in zip(*self.axes.transData.transform([
(i,j) for i,j in zip(self.__x,self.__y)
]))
)
#point distances in figure coordinates
x_fig_dist = (x_fig[1:]-x_fig[:-1])
y_fig_dist = (y_fig[1:]-y_fig[:-1])
r_fig_dist = np.sqrt(x_fig_dist**2+y_fig_dist**2)
#arc length in figure coordinates
l_fig = np.insert(np.cumsum(r_fig_dist),0,0)
#angles in figure coordinates
rads = np.arctan2((y_fig[1:] - y_fig[:-1]),(x_fig[1:] - x_fig[:-1]))
degs = np.rad2deg(rads)
rel_pos = 10
for c,t in self.__Characters:
#finding the width of c:
t.set_rotation(0)
t.set_va('center')
bbox1 = t.get_window_extent(renderer=renderer)
w = bbox1.width
h = bbox1.height
#ignore all letters that don't fit:
if rel_pos+w/2 > l_fig[-1]:
t.set_alpha(0.0)
rel_pos += w
continue
elif c != ' ':
t.set_alpha(1.0)
#finding the two data points between which the horizontal
#center point of the character will be situated
#left and right indices:
il = np.where(rel_pos+w/2 >= l_fig)[0][-1]
ir = np.where(rel_pos+w/2 <= l_fig)[0][0]
#if we exactly hit a data point:
if ir == il:
ir += 1
#how much of the letter width was needed to find il:
used = l_fig[il]-rel_pos
rel_pos = l_fig[il]
#relative distance between il and ir where the center
#of the character will be
fraction = (w/2-used)/r_fig_dist[il]
##setting the character position in data coordinates:
##interpolate between the two points:
x = self.__x[il]+fraction*(self.__x[ir]-self.__x[il])
y = self.__y[il]+fraction*(self.__y[ir]-self.__y[il])
#getting the offset when setting correct vertical alignment
#in data coordinates
t.set_va(self.get_va())
bbox2 = t.get_window_extent(renderer=renderer)
bbox1d = self.axes.transData.inverted().transform(bbox1)
bbox2d = self.axes.transData.inverted().transform(bbox2)
dr = np.array(bbox2d[0]-bbox1d[0])
#the rotation/stretch matrix
rad = rads[il]
rot_mat = np.array([
[math.cos(rad), math.sin(rad)*aspect],
[-math.sin(rad)/aspect, math.cos(rad)]
])
##computing the offset vector of the rotated character
drp = np.dot(dr,rot_mat)
#setting final position and rotation:
t.set_position(np.array([x,y])+drp)
t.set_rotation(degs[il])
t.set_va('center')
t.set_ha('center')
#updating rel_pos to right edge of character
rel_pos += w-used
if __name__ == '__main__':
Figure, Axes = plt.subplots(2,2, figsize=(7,7), dpi=100)
N = 100
curves = [
[
np.linspace(0,1,N),
np.linspace(0,1,N),
],
[
np.linspace(0,2*np.pi,N),
np.sin(np.linspace(0,2*np.pi,N)),
],
[
-np.cos(np.linspace(0,2*np.pi,N)),
np.sin(np.linspace(0,2*np.pi,N)),
],
[
np.cos(np.linspace(0,2*np.pi,N)),
np.sin(np.linspace(0,2*np.pi,N)),
],
]
texts = [
'straight lines work the same as rotated text',
'wavy curves work well on the convex side',
'you even can annotate parametric curves',
'changing the plotting direction also changes text orientation',
]
for ax, curve, text in zip(Axes.reshape(-1), curves, texts):
#plotting the curve
ax.plot(*curve, color='b')
#adjusting plot limits
stretch = 0.2
xlim = ax.get_xlim()
w = xlim[1] - xlim[0]
ax.set_xlim([xlim[0]-stretch*w, xlim[1]+stretch*w])
ylim = ax.get_ylim()
h = ylim[1] - ylim[0]
ax.set_ylim([ylim[0]-stretch*h, ylim[1]+stretch*h])
#adding the text
text = CurvedText(
x = curve[0],
y = curve[1],
text=text,#'this this is a very, very long text',
va = 'bottom',
axes = ax, ##calls ax.add_artist in __init__
)
plt.show()
结果如下所示：
当文本遵循急剧弯曲曲线的凹侧时，仍然存在一些问题。这是因为字符沿曲线“缝合在一起”而没有考虑重叠。如果我有时间，我会努力改进。非常欢迎任何意见。
python在3.5 和 2.7上测试
于 2017-06-13T12:46:05.347 回答
6
我发现你的问题很有趣，所以我使用 matplotlib 文本工具做了一些非常接近的事情：
from __future__ import division
import itertools
import matplotlib.pyplot as plt
import numpy as np
%matplotlib inline
# define figure and axes properties
fig, ax = plt.subplots(figsize=(8,6))
ax.set_xlim(left=0, right=10)
ax.set_ylim(bottom=-1.5, top=1.5)
(xmin, xmax), (ymin, ymax) = ax.get_xlim(), ax.get_ylim()
# calculate a shape factor, more explanation on usage further
# it is a representation of the distortion of the actual image compared to a
# cartesian space:
fshape = abs(fig.get_figwidth()*(xmax - xmin)/(ymax - ymin)/fig.get_figheight())
# the text you want to plot along your line
thetext = 'the text is flowing '
# generate a cycler, so that the string is cycled through
lettercycler = itertools.cycle(tuple(thetext))
# generate dummy river coordinates
xvals = np.linspace(1, 10, 300)
yvals = np.sin(xvals)**3
# every XX datapoints, a character is printed
markerevery = 10
# calculate the rotation angle for the labels (in degrees)
# the angle is calculated as the slope between two datapoints.
# it is then multiplied by a shape factor to get from the angles in a
# cartesian space to the angles in this figure
# first calculate the slope between two consecutive points, multiply with the
# shape factor, get the angle in radians with the arctangens functions, and
# convert to degrees
angles = np.rad2deg(np.arctan((yvals[1:]-yvals[:-1])/(xvals[1:]-xvals[:-1])*fshape))
# plot the 'river'
ax.plot(xvals, yvals, 'b', linewidth=3)
# loop over the data points, but only plot a character every XX steps
for counter in np.arange(0, len(xvals)-1, step=markerevery):
# plot the character in between two datapoints
xcoord = (xvals[counter] + xvals[counter+1])/2.
ycoord = (yvals[counter] + yvals[counter+1])/2.
# plot using the text method, set the rotation so it follows the line,
# aling in the center for a nicer look, optionally, a box can be drawn
# around the letter
ax.text(xcoord, ycoord, lettercycler.next(),
fontsize=25, rotation=angles[counter],
horizontalalignment='center', verticalalignment='center',
bbox=dict(facecolor='white', edgecolor='white', alpha=0.5))
实现远非完美，但在我看来这是一个很好的起点。
此外，在 matplotlib 中似乎有一些关于标记旋转散点图的发展，这对于这种情况来说是理想的。但是，我的编程技能几乎没有解决这个问题所需的核心，所以在这里我无能为力。
于 2017-06-08T21:22:17.570 回答