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好吧，我的任务是将字符串转换为其各自的 unicode 整数，根据所需的加密（左或右以及多少个空格）进行移位。我能够很好地解决这部分问题。但是然后我需要输入移位的 unicode 字符串并将其转换回输入的原始字符串。这是我的代码。我不知道如何将 unicode 字符串转换回原始字符串。**注意 - 我只允许使用整数和字符串。

import java.util.Scanner;
import java.lang.String;
import java.lang.Character;

public class CSCD210_HW2
{
   public static void main(String [] args){
   Scanner input = new Scanner(System.in);
   String str, str1 = "";  
   String encrypt, decrypt = ""; 
   int i = 0; 
   int i1 = (int)0;

      System.out.printf("Please enter a string:"); 
      str = input.nextLine();
      System.out.printf("\nPlease enter encryption format - \'left\' or \'right\'" +
      " \"space\" number of spaces:");
      encrypt = input.nextLine();
      int length = str.length();
      String spaces = encrypt.substring(encrypt.lastIndexOf(' ') + 1); 
      Integer x = Integer.valueOf(spaces);   
      //encrypt
      if (encrypt.startsWith("l")){
         while (i < length){
         int uni = (int)(str.charAt(i++));
         char uni1 = (char)uni;
         int result = uni + x;
         System.out.print(result + " ");}}
      else if (encrypt.startsWith("r")){
         while (i < length){
         int uni = (int)(str.charAt(i++));
         char uni1 = (char)uni;
         int result = uni - x;
         System.out.print(result + " ");}}
      //decrypt
      System.out.printf("\nPlease enter encrypted string:");
      str1 = input.nextLine();
      System.out.printf("\n\'left\' or \'right\' \"space\" number of spaces:");
      decrypt = input.nextLine();
      int length1 = str1.length();
      String spaces1 = decrypt.substring(decrypt.lastIndexOf(' ') + 1);
      Integer y = Integer.valueOf(spaces1);
      if (decrypt.startsWith("l")){
         while (i < length1){
         char word = (char)(str1.charAt(i++));
         int result = word + y;
         System.out.print(result);}}
      else if (decrypt.startsWith("r")){
         while (i < length1){
         char word = (char)(str1.charAt(i++));
         int result = word - y;
         System.out.print(result);}}


   }
}
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1 回答 1

0

您的第二部分没有意义，因为您拥有的加密值基本上是单个字符的 3 位数字。因此，您需要一种方法将 3 个数字转换回 1 个字符，而不是为每个数字创建一个字符。

将其替换为您的第二部分：

  // split the input line containing the encrypted values into single tokens
  // each token represents the numerical values of a single character
  String[] tokens = str1.split("\\s");
  // reserve some space for the characters
  // char[] chars = new char[tokens.length];
  String chars = "";
  // keep track of the position
  // int pos = 0;
  for (String token : tokens)
  {
      if (decrypt.startsWith("l"))
      {
          // convert the string containing the number to integer
          Integer val = Integer.parseInt(token);
          // convert the integer back to char and apply the transformation
          // chars[pos++] = ((char)(val.intValue()+y));
          chars += ((char)(val.intValue()+y));
      }
      else
      {
          // convert the string containing the number to integer
          Integer val = Integer.parseInt(token);
          // convert the integer back to char and apply the transformation
          // chars[pos++] = ((char)(val.intValue()-y));
          chars += ((char)(val.intValue()-y));
      }
  }
  // check if everything worked as expected
  System.out.println(chars);
  // System.out.println(new String(chars));

@Edit：已根据 OP 的需要进行了更新

于 2013-10-13T22:00:31.957 回答