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所以我在保存我的推文时遇到了麻烦，当我收集它们并对其应用 sapply 时，它们以这种形式出现

 some_txt = sapply(tweets, function(x) x$getText())


[1] "RT @JanoImLukesSlut: #HarryHas17MillionFollowParty\n♔ RT\n♔Follow me\n♔Ask4follow back\n♔Follow ALL who RTs\n♔Gain\n♔Drink pepsi feel sexyyy\n#Sto…"               
 [2] "RT @abria_valerie: Pepsi is like crack to me. I gotta have it."                                                                                                                  
 [3] "@JLinn6 having to stop for dr. Pepper bc someone doesn't like Pepsi. #picky #spoiledbrat #watchoutonlylikesdr.'s"                                                                
 [4] "RT @cyberscott1975: The coca cola truck can bugger off! I want a Pepsi Max Xmas Truck!í ½íºš"                                                                                    
 [5] "í ½í²•í ½í²•í ½í²•Mmm That Spicy Chicken Sandwich And Fries And Pepsi From Wendy's Was A1í ½í²¦"                                                                                 
 [6] "@JatnnaP05 @Alexandergr_ @IannErnesto @WilberJE ENTRA dale a GALERIA luego vota por : attabeira https://t.co/hh0Q5tkHzx  #HelpMe"                                                
 [7] "RT @supersunnytime: wallowing in a sea of pop punk and self-hatred"                                                                                                              
 [8] "These bitches love soda Pepsi and Cola"                                                                                                                                          
 [9] "RT @Lmao: waiter: \"what drink would you like\" \nme: \"тнє вℓσσ∂ σƒ му єηємιєѕ\" \nwaiter: \nme: \nwaiter: \nme: \nwaiter: \nme: \nwaiter: \"is pepsi o…"

               .......................

但是，当我对其应用写入 csv 时。然后将其读回它不会返回相同的格式

   write.csv(some_txt, file = file.choose(), row.names = TRUE, sep = ',', col.names = TRUE)
   some_txt = read.csv(file.choose(), row.names = 1, sep = ',')

相反，它返回为

x
1            RT @JanoImLukesSlut: #HarryHas17MillionFollowParty\n♔ RT\n♔Follow me\n♔Ask4follow back\n♔Follow ALL who RTs\n♔Gain\n♔Drink pepsi feel sexyyy\n#Sto…
2                                                                                                               RT @abria_valerie: Pepsi is like crack to me. I gotta have it.
3                                                             @JLinn6 having to stop for dr. Pepper bc someone doesn't like Pepsi. #picky #spoiledbrat #watchoutonlylikesdr.'s
4                                                                                 RT @cyberscott1975: The coca cola truck can bugger off! I want a Pepsi Max Xmas Truck!í ½íºš
5                                                                              í ½í²•í ½í²•í ½í²•Mmm That Spicy Chicken Sandwich And Fries And Pepsi From Wendy's Was A1í ½í²¦
6                                             @JatnnaP05 @Alexandergr_ @IannErnesto @WilberJE ENTRA dale a GALERIA luego vota por : attabeira https://t.co/hh0Q5tkHzx  #HelpMe
7                                                                                                           RT @supersunnytime: wallowing in a sea of pop punk and self-hatred
8                                                                                                                                       These bitches love soda Pepsi and Cola
9  RT @Lmao: waiter: "what drink would you like" \nme: "тнє вℓσσ∂ σƒ му єηємιєѕ" \nwaiter: \nme: \nwaiter: \nme: \nwaiter: \nme: \nwaiter: "is pepsi o…

                                      ......

关于如何将其返回相同值的任何想法？我使用 csv 是因为我想手动收集这些推文。

这是 some_txt 的 str() 示例（这是 50 条推文，这就是它的 1:50 的原因）

  chr [1:50] "@psychicpebble AMEN THANK YOU FOR NOT TALKING ABOUT THAT PEPSI SHIT." ...

编辑：

这是读取后输出的 str() 示例（示例）

     'data.frame':  50 obs. of  1 variable:
     $ x: Factor w/ 43 levels "$39 = Jack'n'Coke, Vodka & Pepsi, and a 24 oz.      Miller Lite. Fml.",..: 10 24 33 9 13 39 9 21 6 31 ...

新更新：我尝试了你的方法 thomas，这不是我想要的，因为在我原来的 some_txt 中我可以做到这一点

  > some_txt[2]
   [1] "RT @Nada_7Q: #تابعني_اتابعك\n@toomy48\n@m_alzuhair\n@alzheri33    \n@hallm77\n@tooomy48\n@RT_FAEF\n@Nada_7Q★☆★☆\n@abosaef11\n@adoan3\n@Msolfje\n@Khalid_06…"
  > some_txt[1]
  [1] "RT @CodeClue: 50 CL Pepsi is unnecessary tbh."
  > some_txt[3]
  [1] "I just ate all my Dad's very expensive cheese and it's supposed to be eaten slowly with a nice glass of red not a Pepsi Max"

将 stringAsFactor 应用到 read.csv 后，它仍然打印出相同的内容，但是 str() 类型略有变化。但我希望整个列表都是 chr[1:50] ，而不仅仅是一个。它也只有一个列表元素，不像我上面的原始 some_txt 。我真的希望有人可以帮助我>.<这让我很头疼

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1 回答 1

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这就是我所做的将其放回其原始形式的列表中。

 for(i in 1:length(some_txt[,1])){
  some_txt1 = c(some_txt1,some_txt[,1][i])
 }

我基本上只是创建了一个 for 循环，然后将它们循环回一个列表中。

于 2013-10-14T09:00:08.727 回答