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这可能是一个愚蠢的问题，不是一个完全与编程相关的问题，但在我尝试学习时请耐心等待。

FEEDLY如何仅通过在搜索框中输入网站 URL 来从网站检索提要/新闻。

例如，我在搜索字段中输入了http://www.inspirationfeed.com，传递的 AJAX 调用/查询字符串为

http://cloud.feedly.com/v3/search/feeds?q=http%3A%2F%2Finspirationfeed.com%2F&n=20&ck=1381664838936

它返回一个 JSON 作为响应

{"results":[{"deliciousTags":["Design","inspiration","Diseño","Web Design","webdesign","graphic design"],"lastUpdated":1381561980000,"score":27531.265625,"website":"http://inspirationfeed.com","title":"inspirationfeed.com","subscribers":1772,"language":"en","velocity":16.3,"feedId":"feed/http://feeds.feedburner.com/inspirationfeed/BTLD","description":"be inspired!"},{"deliciousTags":["DESIGN","Inspiration"],"lastUpdated":1381474380000,"score":48.0,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Inspiration","subscribers":48,"language":"en","velocity":4.7,"feedId":"feed/http://inspirationfeed.com/category/inspiration/feed/","description":"be inspired!"},{"deliciousTags":["design"],"lastUpdated":1381479900000,"score":294.7439270019531,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Articles","subscribers":27,"language":"en","velocity":11.7,"feedId":"feed/http://inspirationfeed.com/category/articles/feed/","description":"be inspired!"},{"deliciousTags":["Photography"],"lastUpdated":1381129620000,"score":17.0,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Photography","subscribers":17,"language":"en","velocity":0.7,"feedId":"feed/http://inspirationfeed.com/category/photography/feed/","description":"be inspired!"},{"deliciousTags":["Little Bit of Everything-Amatuer"],"lastUpdated":1381396020000,"score":109.16442108154297,"website":"http://inspirationfeed.com","title":"inspirationfeed.com » Blogging","subscribers":10,"language":"en","velocity":0.5,"feedId":"feed/http://inspirationfeed.com/category/articles/blogging/feed/","description":"be inspired!"}]}

我的理解

1）基于键deliciousTags，feedly 生成#标签 2）基于键score，feedly 以自上而下的顺序排列站点中可用的不同提要/新闻 URL

我不懂的是

1）feedly如何通过输入网站URL来获取news feed / rss URL（示例 "feedId":"feed/http://feeds.feedburner.com/inspirationfeed/BTLD"：）

2）需要为这样的事情编写什么类型的Web服务。它是否需要服务器端脚本来对相关网站进行深度搜索并检索提要 URL？是否可以使用 JQuery/Javascript 在客户端本身获取提要 URL？

再次感谢您花时间阅读问题。

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1 回答 1

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在页面 html 的头部有一个带有 rss/atom 提要的站点的链接，如下所示：

<link rel="alternate" type="application/atom+xml" title="Feed for question &#39;how does a service like feedly obtain the rss feeds from a website when the website URL is entered into the search box(not the feed url&#39;" href="/feeds/question/19345075">

这是这个问题的页面来源

Feedly 或类似在该页面的 html 中搜索的服务（不是主机）并找到此链接标签（带有 rel、type）：<link rel="alternate" type="application/atom+xml" title="awd" href="/feedUrl">或<link rel="alternate" type="application/rss+xml" title="awd" href="/feedUrl">（还有更多）

还有一些设置提要网址的例程，

  • http://<url>/rss
  • http://<url>/feed
  • http://<url>/atom
  • http://<url>/<page>.xml

如果没有找到，那么那里什么都没有！

它可以在服务器端和客户端完成，但在服务器端有更多的好处，比如在解析页面 html 和测试例程之前进行数据库搜索。

默认情况下，Firefox 有一个获取页面提要的选项，以前版本的 chrome 具有这样的功能，但它被谷歌（和谷歌方式）删除。（这是浏览器端，由用户控制和拥有的网站不能使用！但您可以找到他们实现该方法的方式）

于 2013-10-13T22:57:29.640 回答