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我目前正在使用 select 语句在不同的时间间隔内使用 1 个 kiosk 系统慢慢获取不同会员类别的会员惠顾。

SELECT COUNT(MemberID) from Member where signin >= '13-10-2013 09:00' and signout <= '13-10-2013 15:00' and MemberType = 1 and kioskid = 1

SELECT COUNT(MemberID) from Member where signin >= '13-10-2013 15:00' and signout <= '13-10-2013 20:00' and MemberType = 1 and kioskid = 1

SELECT COUNT(MemberID) from Member where signin >= '13-10-2013 09:00' and signout <= '13-10-2013 15:00' and MemberType = 2 and kioskid = 1

SELECT COUNT(MemberID) from Member where signin >= '13-10-2013 15:00' and signout <= '13-10-2013 20:00' and MemberType = 2 and kioskid = 1

有没有办法让我在一个查询中一起抓取数据，如下所示：

                |  09:00 - 15:00  |  15:00 - 20:00
Premium Member  |       21        |       55
Standard Member |       100       |       300
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2 回答 2

0

是的，你可以这样做：

select * from (
select 'Premium Member' mt, a.cnt "9-15", b.cnt "15-20" from 
(SELECT COUNT(MemberID) cnt from Member where signin >= '13-10-2013 09:00' and signout <= '13-10-2013 15:00' and MemberType = 1 and kioskid = 1) a, ( SELECT COUNT(MemberID) cnt from Member where signin >= '13-10-2013 15:00' and signout <= '13-10-2013 20:00' and MemberType = 1 and kioskid = 1) b
union
select 'Standard Member' mt, c.cnt "9-15", d.cnt "15-20" from 
(SELECT COUNT(MemberID) from Member where signin >= '13-10-2013 09:00' and signout <= '13-10-2013 15:00' and MemberType = 2 and kioskid = 1) c, (SELECT COUNT(MemberID) from Member where signin >= '13-10-2013 15:00' and signout <= '13-10-2013 20:00' and MemberType = 2 and kioskid = 1) d
)

我有硬编码的成员类型，因为我在您的查询中看不到成员类型 ID 和成员类型名称之间的任何映射。如果存在这样的映射，则可以替换它。

于 2013-10-13T07:24:28.803 回答
0

您可以使用子查询和分组依据来做到这一点

select MemberType, 
    COUNT(MemberID in (select MemberID 
                       from Member 
                       where signin >= '13-10-2013 09:00' and signout <= '13-10-2013 15:00')),
    COUNT(MemberID (select MemberID 
                    from Member 
                    where signin >= '13-10-2013 15:00' and signout <= '13-10-2013 20:00')) 
from Member 
group by MemberType
于 2013-10-13T07:24:34.750 回答